(a + 2b + 3c) − (4a + 6b − 5c) is equivalent to:A. −4a − 8b − 2c
B. −4a − 4b + 8c
C. −3a + 8b − 2c
D. −3a − 4b − 2c
E. −3a − 4b + 8c

Answers

Answer 1

Answer: $(a + 2b + 3c) - (4a + 6b - 5c)= a + 2b + 3c - 4a - 6b + 5c =\n \n= -3a -4b +8c \n \nAnswer : \ E. \ \ -3a- 4b + 8c$

Answer 2

Answer: = a + 2b + 3c - 4a - 6b + 5c
= ( -3a - 4b + 8c )
Hence the answer is option E

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The length of each of the sides of a pentagon are 4x - 2. Which equation can be used to find p, the perimeter of the pentagon?

Answers

The answer is 5(4x-2).
There are 5 sides in a Pentagon so just multiply a side by 5.

Does anyone know this?

( 11 + 4) ÷ 3 × √64

Answers

Answer:

oh i used an algebra helper and got that answer i had, but i searched on googIe after that and got 40

Answer:

Step-by-step explanation:

Following the order of operations you need to do the parenthases first and 11+4 is 15. Then you divide that by 3 which is 5. Then you are going to need to multiply 5 × √64 which the square root of 64 is 8 so you multiply 5 × 8 which is 40.

If the circumference of a circle is 2pi, what is the area?

Answers

Circumference of a circle= 2 * pi * r

Plug in what we know: 2pi = 2 * pi * r

Divide 2 pi to both sides: r = 1 (anything divided by itself is equal to 1)

Area = pi * r^2

Plug in what we know: A = pi * 1^2
A = pi * 1 ==> A = 1 pi

So the area is '1 pi' or just 'pi'.

The circumference of a circle is (pi) x (diameter).

The circumference of this circle is 2pi, so

2 pi = (pi) x (diameter).

So the diameter of this particular circle is 2,
Its radius is 1/2 of the diameter, so radius = 1.

The reason we need to know the radius is
because it's needed to find the area.

The area of any circle is (pi) x (radius squared).
For this particular circle ...

Area = (pi) x (1 squared) = pi square units .

there was 135 buttons in a jar after Robin put more bottons into the jar there were 175 bottons in the jar how many groups of 10 bottons did she put into the jar

Answers

the correct answer is 4

13 if your staring from zero

Can someone please help me

Answers

The point-slope form:

$y-y_1=m(x-x_1)\n\nm=(y_2-y_1)/(x_2-x_1)$

We have two points (-2, -6) and (0, -2). Substitute:

$m=(-2-(-6))/(0-(-2))=(4)/(2)=2\n\ny-(-6)=2(x-(-2))\n\ny+6=2(x+2)\qquad|\text{use distributive property}\n\ny+6=2x+4\qquad|\text{subtract 6 from both sides}\n\ny=2x-2\qquad|\text{subtract 2x from both sides}\n\n-2x+y=-2\qquad|\text{change the signs}\n\n2x-y=2$