a club had some money to purchase new chairs after buying 355chairs at 199$ there was 1068$ remaining how much money did the club had first

Answers

Answer 1
Answer:

The amount of money the club had first is $71,713

  • The chair purchased by the club is = 355 chairs
  • The total price per chair = 119
  • The money the club has after purchase = 1068

Further Explanation

To determine how much money the club has first, we can derive solution to it by using the area model method. (Please refer to the attachment below)

What we should do first is to calculate the total amount of money spend on chairs by multiplying the chair purchased and the price per each chair

Therefore, we have:

355 x 199

= (300 + 50 + 5) x (100 + 90 + 9)

= (300 x 100) + (300 x 90) + (300 x 9) + (50 x 100) + (50 x 90) + (50 + 9) (5 x 100) + (5 x 90) + (5 x 9)

= 30000 + 27000 + 2700 + 5000 + 4500 + 450 + 500 + 450 + 45

= 70645

Therefore, the total money spend on chairs is 70,645

Recall, we have to calculate the money the club has first before purchase, then we can derive this by adding the total money spend on chairs and the money the club has after purchase.

Therefore we have:

= 70645 + 1068

= 71,713

Therefore, the money the club has at first before purchasing new chairs is 71,713.

You can also solve this question quickly by following this step:

You can also solve this quickly by multiplying the chair purchased by the club and the price per each chair, then the value derived should be added to the money the club has after purchase.

Hence,

= 355 x 199

= 70645

= 70645 + 1068

= 71,713.

LEARN MORE:

KEYWORDS:

  • 355 chairs
  • club
  • $199
  • area model
  • multiplying
  • adding
Answer 2
Answer: Multiply 199 by 355 to give you 70,645. Then add 70,645 to 1068 to give you 71,713.

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Would a field with a width of 75 yards as an area of 7500 square yards be within fifa regulation

Answers

we know that

Based on the FIFA rules for international matches,  dimensions of fields are: Length: minimum 100 m, maximum 110 m. Width: minimum 64 m, maximum 75 m.

we know that

The area of a rectangle is

A=L*W

where

L is the length side of the field

W is the width side of the field

In this problem we have

W=75\ yd\nA=7500\ yd^(2)

Step 1

Find the value of L

A=L*W

L=A/W

substitute the values

L=7500/75=100\ yd

Step 2

Convert yards to meters

we know that

1 \ yard =0.9144\ meters

L=100\ yard=100*0.9144=91.44\ meters

W=75\ yard=75*0.9144=68.58\ meters

Step 3

Compare the dimensions of the field with the dimensions of FIFA regulation

Length: minimum 100 m, maximum 110 m

Length of the field=91.44\ meters

The length does not satisfy the measures of the FIFA regulation

because

91.44\ meters < 100\ meters

therefore

the answer is

The field does not satisfy the measures of the FIFA regulation

Final answer:

The length of the field is calculated as 7500/75 = 100 yards. As per FIFA regulations, the length of a football field should be between 100-130 yards and the width should be between 50-100 yards. Therefore, a field of length of 100 yards and a width of 75 yards is within the FIFA regulations.

Explanation:

The area of a rectangle can be calculated using the formula Area = length x width. In the case of a football field, if the width is 75 yards, and the total area is 7500 sq yards, we can find the length by making length the subject of the formula, which then becomes Length = Area/Width. Substituting the given values we get, Length = 7500/75 = 100 yards.

According to FIFA regulations, for international matches, the field dimensions should be: Length (touch line) should be a minimum of 100 yards and a maximum of 130 yards. The width (goal line) should be a minimum of 50 yards and a maximum of 100 yards. So, a field with 100 yards in length and 75 yards in width fits within FIFA regulations.

Learn more about FIFA regulations here:

brainly.com/question/32425335

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