How would you round off a number to one decimal place? For example would 67.39 become 67.4

Answers

Answer 1

Answer: you take the second decimal, and if it is 5 or over, you increase the first decimal by one. If the number is 17.96,you increase the first decimal by one which gives you 18. If the question asks for 1 decimal place, than put 18.0 :)

Answer 2

Answer:

when rounding off numbers to specific decimal places look at the number after that place. If that number is less than 5 then keep the needed decimal the same. if it is greater than 5 then round up by one.

Examples:

15.69 ⇒ 15.7
15.64 ⇒ 15.6

17.890 ⇒ 17.89
17.898 ⇒ 17.90

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Submit your work legible (ifSwill and answerin a webmail to me. This is a total of 35 points. Itbe a portfolio gradyou will have to webmail me this!Complete the following problems.1. Open Response: Solve each problem below. Solve for the missing side, Show your workGive both an exact answer and Rn answer in your solutions.

Answers

ok so

for a right triangle with legs legnth a and b and hypotonuse c
a^2+b^2=c^2
remember
the hypotonuse is the side oposite the right angle

you have
13 and 17 and x
17=hypotonuse
13 ad x are legs
13^2+x^2=17^2
169+x^2=289
minus 169 boh sides
x^2=120
sqrt both sides
x=2√30
aprox
10.9545 units

second one
legs are 5x and x
hypotonsue is 20
(5x)^2+x^2=20^2
25x^2+x^2=400
26x^2=400
divide both sides by 26
x^2=(400/26)
sqrt both sides
x=20/(√26)
aprox
x=3.92232 units
times 5 to see other leg
19.616 units

A bicyclist travels at the rate of 8 miles in an hour. If the bicyclist continues at this rate, how many miles can the bicyclist travel in five hours?

Answers

they would 40 miles in 5 hours traveling at 8 miles an hour

The bicyclist traveled 40 miles in 8 hours so the answer is D) 40 miles it is correct i took the test

Simplify the expression

Answers

Answer:

f(x) = 5x² + 2x

g(x) = 6x - 6

Step-by-step explanation:

$(5x^3-8x^2-4x)/(6x^2-18x+12)\n\n6(x^2-3x+2)\ne0\ \iff\ x=(3\pm√(9-8))/(2)\ne0\ \iff\ x\ne2\ \wedge\ x\ne1\n\n\n(5x^3-8x^2-4x)/(6x^2-18x+12)=(x(5x^2-8x-4))/(6(x^2-3x+2))=(x(5x^2-10x+2x-4))/(6(x^2-2x-x+2))=\n\n\n=(x[5x(x-2)+2(x-2)])/(6[x(x-2)-(x-2)]) =(x(x-2)(5x+2))/(6(x-2)(x-1))=(x(5x+2))/(6(x-1))=(5x^2+2x)/(6x-6)\n\n\nf(x)=5x^2+2x\n\ng(x)=6x-6$

Use integration by parts to integrate sin2x between pi and 0

Answers

Answer:

$\displaystyle \int\limits^0_(\pi) {\sin (2x)} \, dx = 0$

General Formulas and Concepts:

Calculus

Integration

Integrals

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

U-Substitution

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \int\limits^0_(\pi) {\sin (2x)} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution.

Set u: $\displaystyle u = 2x$
[u] Differentiate: $\displaystyle du = 2 \ dx$
[Bounds] Switch: $\displaystyle \left \{ {{x = 0 ,\ u = 2(0) = 0} \atop {x = \pi ,\ u = 2 \pi}} \right.$

Step 3: Integrate Pt. 2

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int\limits^0_(\pi) {\sin (2x)} \, dx = (1)/(2) \int\limits^0_(\pi) {2 \sin (2x)} \, dx$
[Integral] U-Substitution: $\displaystyle \int\limits^0_(\pi) {\sin (2x)} \, dx = (1)/(2) \int\limits^0_(2 \pi) {\sin u} \, du$
Trigonometric Integration: $\displaystyle \int\limits^0_(\pi) {\sin (2x)} \, dx = (1)/(2)(-\cos u) \bigg| \limits^0_(2 \pi)$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^0_(\pi) {\sin (2x)} \, dx = (1)/(2)(0)$
Simplify: $\displaystyle \int\limits^0_(\pi) {\sin (2x)} \, dx = 0$