A 9.0 volt battery is connected to four resistors in a parallel circuit. The resistors have 7.0 Ω, 5.0 Ω, 4.0 Ω, and 2.0 Ω respectively. What is the total current in the circuit?

Answers

Answer 1
Answer: series,effective resistance =R₁+R₂+R₃...
parallel,effective resistance 1/R=1/R₁ +1/R₂ +1/R₃...
 
Here,effective resistance 1/R =1/7 +1/5+ 1/4+1/2  
                                           =1.092
                                       R = 1/1.092 =0.915Ω
voltage V=9 V 
current I=V/R
           
I=9 / 0.915
            =9.83 A
Answer 2
Answer: parallel resistance = (1)/(7)(1)/(5)(1)/(4)(1)/(2)
=(140)/(153)

now , V= 9V
V = IR
I = (V)/(R)
I = (9)/(140) x 153
I = 9.835714 A


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Answers

Answer:

6.17 m

Explanation:

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