How many parsecs can a particular person parse if a person could parse a particular parsec

Answers

Answer 1

Answer:
A parsec is a unit of distance. It's not something that a parson can parse.

Answer 2

Answer:

Final answer:

A parsec is a unit of distance used in astrophysics to measure the distance between celestial objects. It is equal to 3.26 light-years or approximately 31 trillion kilometers.

Explanation:

A parsec is a unit of distance used in astrophysics to measure the distance between celestial objects. It is equal to 3.26 light-years or approximately 31 trillion kilometers. The concept of a parsec is based on stellar parallax, which is a method used to calculate distances to nearby stars.

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Which one of the following accurately describes the force of gravity

Answers

The force of gravity, also called gravitational force, is the force exerted by the gravity of one object to another object near it. This is dependent on factors like mass of the two objects measured between their centers.

The moon's mass is 7.35 × 1022 kg, and it moves around the earth approximately in a circle or radius 3.82 × 105 km. The time required for one revolution is 27.3 days. Calculate the centripetal force that must act on the moon. How does this compare to the gravitational force that the earth exerts on the moon at that same distance?

Answers

Explanation:

It is given that,

Mass of moon, $m=7.35* 10^(22)\ kg$

Radius of circle, $r=3.82* 10^(5)\ km=3.82* 10^(8)\ m$

The time required for one revolution is 27.3 days, t = 27.3 days

1 day = 86400 seconds

27.3 days = 2358720 seconds

Let v is the speed of moon around the circular path. It is given by :

$v=(2\pi r)/(T)$

$v=(2\pi * 3.82* 10^(8)\ m)/(2358720\ s)$

v = 1017.57 m/s

Let F is the centripetal force acting on the moon. It is given by :

$F=(mv^2)/(r)$

$F=(7.35* 10^(22)\ kg* (1017.57\ m)^2)/(3.82* 10^(8)\ m)$

$F=1.99* 10^(20)\ m/s^2$

So, the centripetal force that must act on the moon is $1.99* 10^(20)\ m/s^2$ . The gravitational force that the earth exerts on the moon at that same distance is also equal to $1.99* 10^(20)\ m/s^2$ . Hence, this is the required solution.

A 25.6-kg child pulls a 4.81-kg toboggan up a hill inclined at 25.7° to the horizontal. The vertical height of the hill is 27.3 m. Friction is negligible.(a) Determine how much work the child must do on the toboggan to pull it at constant velocity
up the hill.
(b) Repeat (a) if the vertical height is still 27.3 m, but the angle is 19.6°. What general conclusion can you make?
(c) The child now slides down the hill on the toboggan. Determine the total work on the child and toboggan during the slide.

Answers

Explanation:

(a) To determine the work the child must do on the toboggan to pull it at constant velocity up the hill, we can use the work-energy principle.

1. Calculate the gravitational potential energy of the toboggan at the top of the hill:

- Gravitational potential energy = mass * gravity * height

- Mass of the toboggan = 4.81 kg

- Gravity = 9.8 m/s^2 (approximate value)

- Height = 27.3 m

- Gravitational potential energy = 4.81 kg * 9.8 m/s^2 * 27.3 m

2. Calculate the work done by the child:

- The work done is equal to the change in gravitational potential energy.

- Since the toboggan is pulled at constant velocity, the work done is equal to the negative of the change in gravitational potential energy.

- Work done by the child = - (4.81 kg * 9.8 m/s^2 * 27.3 m)

(b) To repeat part (a) with a different angle, we need to recalculate the gravitational potential energy and work done.

1. Calculate the new height:

- Height = 27.3 m

2. Calculate the new work done:

- Work done by the child = - (4.81 kg * 9.8 m/s^2 * 27.3 m)

General conclusion:

When the vertical height remains the same, but the angle decreases, the work done by the child to pull the toboggan at constant velocity up the hill remains the same. This indicates that the angle of the incline does not affect the amount of work done in this scenario.

(c) When the child slides down the hill on the toboggan, both gravitational potential energy and kinetic energy are involved. The total work done on the child and toboggan during the slide can be calculated as the change in mechanical energy.

1. Calculate the initial gravitational potential energy at the top of the hill:

- Gravitational potential energy = mass * gravity * height

- Mass of the child and toboggan combined = 25.6 kg + 4.81 kg

- Height = 27.3 m

- Gravitational potential energy = (25.6 kg + 4.81 kg) * 9.8 m/s^2 * 27.3 m

2. Calculate the final kinetic energy at the bottom of the hill:

- Kinetic energy = 0.5 * mass * velocity^2

- Mass of the child and toboggan combined = 25.6 kg + 4.81 kg

- Velocity = calculated using the conservation of mechanical energy, assuming no energy losses due to friction or other factors

3. Calculate the total work done:

- Total work done = change in mechanical energy

- Change in mechanical energy = final kinetic energy - initial gravitational potential energy

Therefore, to determine the total work done on the child and toboggan during the slide, we need to calculate the initial gravitational potential energy and the final kinetic energy.

I hope this helps :)

A. When changing lanes, what are the safety steps to follow? B. What are the additional steps to follow when passing?

Answers

A. check your mirrors and blindspots carefully for any potential hazards
B. Scan for hazards, e.g., oncoming vehicles, vehicles approaching from rear, merging vehicles;
Check for blind spots;
Signal your intention and accelerate into passing lane;
Accelerate quickly to an appropriate speed

What is meant by fundamental unit? write any two difference between mass and weight.

Answers

Answer:

Fundamental unit is any unit that is not dependent on other units and other units can be derived from them

Explanation:

Units such as Kilogram, Mass and Time are said to be fundamental units because they are independent.

Differences between Mass and weight;

1. Mass is the measure of the amount of matter in a body while weight is a measure of how the force of gravity acts upon that mass.

2. Mass is a scalar quantity while weight is a vector quantity

How long will it take a car to accelerate from 15.2 to 23.5 m/s if the car has an average acceleration of 3.2 m/s?

Answers

It will take a car, 2.59 s to accelerate from 15.2 to 23.5 m/s.

What is Speed?

speed is described as. the pace at which an object's location changes in any direction. Speed is defined as the distance traveled divided by the travel time. Speed is a scalar quantity because it just has a direction and no magnitude.

Given, the car has an average acceleration of 3.2 m/s².

To solve this problem, we can use the following kinematic equation:

v = u +at

where:

v is the final velocity (23.5 m/s)

u is the initial velocity (15.2 m/s)

a is the acceleration (3.2 m/s^2)

t is the time

We can rearrange this equation to solve for t:

t = (v -u)/a

substituting the values we have:

t = (23.5 - 15.2 ) / 3.2

t = 2.59375 seconds

Therefore, it will take approximately 2.59 seconds for the car to accelerate from 15.2 m/s to 23.5 m/s with an average acceleration of 3.2 m/s².

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Hello!

How long will it take a car to accelerate from 15.2 m/s to 23.5 m/s if the car has an average acceleration of 3.2 m/s² ?

We have the following data:

Vf (final velocity) = 23.5 m/s

Vi (initial velocity) = 15.2 m/s

ΔV (speed interval) = Vf - Vi → ΔV = 23.5 - 15.2 → ΔV = 8.3 m/s

ΔT (time interval) = ? (in s)

a (average acceleration) = 3.2 m/s²

Formula: