Factor using ac-method and factor completely, 25x²-30x--40 (help)

Answers

Answer 1

Answer: $25x^2-30x-40=\n 5(5x^2-6x-8)=\n 5(5x^2-10x+4x-8)=\n 5(5x(x-2)+4(x-2))=\n 5(5x+4)(x-2)$

Answer 2

Answer: Answer : $25x^2-30x-40 \n =5(5x^2-10x+4x-8) \n =5[5x(x-2)+4(x-2)] \n =5(x-2)(5x+4)$

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Answers

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Answers

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10x – 2y = -6

Answers

Answer:

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Step-by-step explanation:

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Answers

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Let $ A $ and $ B $ be events with $ P(A)=1 / 3 $ and $ P(B)=2 / 3 $. Let $ N $ be the number of events from among $ A $ and $ B $ that occur. (For instance, if $ A $ occurs but $ B $ does not, then $ N=1 $.) Suppose that the occurrence of events in $ A $ and $ B $ are independent. Find, for example, the probability that no events occur.

Answers

Answer:

( 2/9 )

Step-by-step explanation:

Okay, so since the events A and B are independent, the probability that both of them do not occur is the product of their individual probabilities of not occurring.

The probability of event A not occurring, denoted as ( P(A') ), is equal to 1 minus the probability of A occurring. Similarly, the probability of event B not occurring, denoted as ( P(B') ), is equal to 1 minus the probability of B occurring.

So, ( P(A') = 1 - P(A) = 1 - 1/3 = 2/3 ) and ( P(B') = 1 - P(B) = 1 - 2/3 = 1/3 ).

Since A and B are independent, the probability that both A and B do not occur is simply the product of their individual probabilities of not occurring:

[ P(N = 0) = P(A' cap B') = P(A')P(B') = (2/3) times (1/3) = 2/9 ]

So, the probability that no events occur is ( 2/9 ).

Hope this helps! :)

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