The atoms having partially filled shells have orbitals with electrons half or less than the number of electrons that can be accomodated in it. The atom which has a partially filled second electron shell in the ground state is lithium.
Lithium is 3rd element in periodic table and thus having 3 electrons in it. The main shell electronic configuration of lithium is written as K=2, L=1. Thus the second shell L has only one electron and it is said to be partially filled.
The element hydrogen is having only one electron located in the K shell and it have o more shells which are filled.
The elements sodium and potassium are first group elements sodium with 11 electrons and potassium atom with 19 electrons. Both are having 3 main shells and one electron in the last shell. Thus their second shell is completely filled.
Hence, the atom which have partially filled second electron shell in the ground state among the following is lithium. Thus, option B is correct.
To find more about lithium, refer the link below;
#SPJ2
Answer:
Therefore, the steepest slope in the graph indicates that the sprinter is experiencing a rapid increase in speed during the early stages of the race. This suggests that Jesse Owens had a powerful start and was able to accelerate quickly in the 100m dash.
Explanation:
Based on the graph provided, the point where the graph appears to have the steepest slope is around the 2-second mark.
The steep slope in the graph represents the sprinter's acceleration during the initial phase of the race. In the 100m dash, sprinters aim to reach their top speed as quickly as possible. The steeper the slope, the faster the sprinter is accelerating.
To determine how much of a 144g sample of carbon-14 will remain after 1.719 x 10^4 years, you can use the formula for exponential decay:
\[N(t) = N_0 \cdot \left(\frac{1}{2}\right)^{\frac{t}{T}}\]
Where:
- \(N(t)\) is the remaining amount after time \(t\).
- \(N_0\) is the initial amount.
- \(t\) is the time that has passed.
- \(T\) is the half-life.
In this case, \(N_0\) is 144g, \(t\) is 1.719 x 10^4 years, and \(T\) is the half-life of carbon-14, which is 5,730 years.
Plug these values into the formula:
\[N(t) = 144g \cdot \left(\frac{1}{2}\right)^{\frac{1.719 \times 10^4\text{ years}}{5,730\text{ years}}}\]
Now, calculate:
\[N(t) = 144g \cdot \left(\frac{1}{2}\right)^{\frac{3}{2}}\]
\[N(t) = 144g \cdot \left(\frac{1}{2} \cdot \frac{1}{2} \cdot \frac{1}{2}\right)\]
\[N(t) = 144g \cdot \frac{1}{8}\]
Now, multiply 144g by 1/8 to find the remaining amount:
\[N(t) = \frac{144g}{8} = 18g\]
So, after 1.719 x 10^4 years, only 18g of the 144g sample of carbon-14 will remain.
1.) Calcium and Bromine
2.) Sodium and Fluorine
3.) Lithium and Chlorine
4.) Magnesium and Argon
B
It changes direction when it passes through an opening
С
It changes its speed and wavelength when it passes through an opening
D
It changes direction when it passes from one medium to another
E
It changes its speed and wavelength from one medium to another.
F
It changes direction when it bounces off of a solid surface.
If a sound wave refracts,It changes its speed and wavelength when it bounces off of a solid surface,It changes its speed and wavelength when it passes through an opening, and It changes direction when it passes from one medium to another. Therefore, option A, C and D are correct.
An important case in which sound waves change form or spread out is called refraction. This phenomenon affects the bending of a sound wave owing to changes in the wave's speed.
Refraction is the reason ocean waves near a shore parallel to the beach and why glass lenses can be used to focus light waves.
If the air above the earth is warmed than that at the surface, sound will be change shape back downward toward the surface by refraction. Soundpropagates in all directions from a point source.
Thus, option A, C and D are correct.
To learn more about the refraction of sound wave, follow the link;
#SPJ6