Number 33 apparently the answer is 4 but I have no idea why
Answers
in the picture. Fortunately, you caught the whole question in the picture of #32.
Tools you need in order to answer this one:
-- When the frequency of a wave goes up, the wavelength gets shorter.
(That's why the high numbers on a radio receiver are called 'short-wave'.)
-- Photons with higher frequency carry more energy.
(That's why x-rays and gamma rays are dangerous to our delicate human tissues.)
Do you remember hearing these things in class ?
Anyway, as the frequency of the photons increases, their
energy increases, and their wavelengths get shorter.
I hope that's one of the choices that escaped getting caught in the photo.
Related Questions
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How do the units of work and power compare? a) The unit for work is a watt. The unit for power is a joule, which is a watt-second. b)The unit for work is a watt. The unit for power is a joule, which is a watt per second. c)The unit for work is a joule. The unit for power is a watt, which is a joule-second. d)The unit for work is a joule. The unit for power is a watt, which is a joule per second.
When it comes to our place in the solar system today which model do we accept
What force keeps a water spider on the surface of water
B. 273 K
C. 560 K
D. 140 K
Answers
PV/T = constant. P will also be constant in this giving us:
V₁/T₁ = V₂/T₂
40/320 = 20/T₂
T₂ = 160 K
The answer is A.
Answer:
The correct answer is option A.
Explanation:
Initial volume of the gas
Initial temperature of gas
Final volume of the gas
Final temperature of the gas =
Applying Charles' Law:
The temperature of the gas when volume of the gas is 20.0 L is 160 K.Hence, the correct answer is option A.
Answers
Whatever your experiment maybe, the full steps to avoid any casualties and make the experiment as safe as possible should be included in the procedure/ instructions.
hope this helps
Answer:
the correct answer is a
Explanation:
performing the experiment in a
safe manner
Answers
Answer:
acceleration for time interval from 1 sec to 4 second is 1.5 metre/second^2
mark it as brainliest!!
wire has a resistance of 1.3 ohms. The crosssectional
area of this wire is
(1) 7.9 × 10^−8 m2 (3) 4.6 × 10^0 m2
(2) 1.1 × 10^−7 m2 (4) 1.3 × 10^7 m2
Answers
The cross-sectional area of the copper wire is which has 1.3 ohm at 20 degree Celsius during laboratory experiment by student is 7.9×10⁻⁸ ohm.
What is the resistance?
Resistance is obstacle for the current flow in the circuit. It is the measure of reverse act to current flow in through a material. It can be given as,
Here, (ρ) is the specific resistance (l) is the length of the wire and (A) is the cross-sectional area of the wire.
During a laboratory experiment, the student finds that at 20° Celsius, a 6.0-meter length of copper wire has a resistance of 1.3 ohms.
The value of resistivity of copper wire is 1.72×10⁻⁸ ohm-m. Put these values in the above formula as,
Thus, the cross-sectional area of the copper wire is which has 1.3 ohm at 20 degree Celsius during laboratory experiment by student is 7.9×10⁻⁸ ohm.
Learn more about the resistance here;
ρ = resistivity of copper at 20 °C = 1.72 x 10⁻⁸ ohm-m
R = resistance of the copper wire = 1.3 ohm
L = length of the copper wire = 6 meter
A = area of cross-section of the copper wire = ?
Resistivity of copper wire is given as
R = ρL/A
inserting the values in the above equation
1.3 = (1.72 x 10⁻⁸) (6)/A
A = 7.9 x 10⁻⁸ m²
Hence the correct choice is
(1) 7.9 x 10⁻⁸ m²
Answers
Answer:
A. 45 degrees
Explanation:
A projectile travels the farthest when it is launched at an angle of 45 degrees.
The maximum range is 45 degrees, ignoring air resistance.
sin(2θ) = 1
∴ 2θ = π/2.
(2θ)/2 = (π/2)/2
θ = π/4
π/4 or 45°
Answer:
A. 45 degrees
Explanation:
Answers
Final answer:
The mass of the aluminum added is calculated through the principle of conservation of energy, specifically thermal energy. By considering the heat lost by the aluminum and gained by the water, we can rearrange the equation for heat transfer and find that the mass of the aluminum is approximately 37.9 grams.
Explanation:
In this physics question, we're looking at a thermodynamic process involving a chunk of aluminum and water. Given the known values of their respective specific heats, the mass of water, and their final equilibrium temperature, we're aiming to find the mass of the aluminum.
We begin by understanding that in a closed system, the heat gained by one body is equal to the heat lost by another. In this case, the aluminum is losing heat, and the water is gaining it. The equation for heat transfer (Q = mcΔT), where m is mass, c is specific heat, and ΔT is change in temperature.
The heat gained by the water = mass of water * specific heat of water * change of temperature in water = 200g * 4.18J/g°C * (18.9°C - 15.5°C) = 2836.4J.
This is equal to the heat lost by the aluminum. Solving the analogous heat equation for the mass of the aluminum gives us the answer:
m = Q / (c * ΔT) = 2836.4J / (0.897J/g°C * (91.4°C - 18.9°C)) = 37.9g
So the mass of the aluminum is approximately 37.9 grams.
Learn more about Thermodynamics here:
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