Roster method of months with 31 days

Answers

Answer 1

Answer: A={January,march,may,july,august,october,december}

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Deb had a board that measures 5 feet in length. How many 1/4-foot long pieces can deb cut from the board?
Write the number equal to 5 tens and 13 ones
What is the value of the expression 8with a exponent of -2?
1: a 24 ounce box of cornflakes cost $4.59?2: a 36 ounce box of cornflakes cost $5.79?what are the unit rates for those two and one more question: which is the better gbuy
I nEeD hElP pLeAsE :)

Write an inequality for each situation
There are at least 24 pictures on the roll of film.

Answers

x ≥ 24
It has to be at the very least 24

Its kinda hard to type but i hope you get what i wrote
x< 24
-

Solve each questions by taking square roots1.k²=76
2.k²=16
3.x²=21
4.a²=40
5.x²+8=28
6.2n²=-144
7.-6m²=-414
8.7x²=-21
9.m²+7=88
10.-5x²=-500
11.-7n²=-448
12.-2k²=-162
13.x²-5=73
14.16n²=49

Answers

$1.\ k^2=76\n\nk=\pm√(76)\n\nk=\pm√(4\cdot19)\n\nk=\pm2√(19)\n-------------\n2.\ k^2=16\n\nk=\pm√(16)\n\nk=\pm4\n-------------\n$
$3.\ x^2=21\n\nx=\pm√(21)\n-------------\n4.\ a^2=40\n\na=\pm√(40)\n\na=\pm√(4\cdot10)\n\na=\pm2√(10)\n-------------\n5.\ x^2+8=28\ \ \ /-8\n\nx^2=20\n\nx=\pm√(20)\n\nx=\pm√(4\cdot5)\n\nx=\pm2\sqrt5\n-------------\n$
$6.\ 2n^2=-144\ \ \ \ /:2\n\nn^2=-72-no\ real\ solutions\n-------------\n7.\ -6m^2=-414\ \ \ \ /:(-6)\n\nm^2=69\n\nm=\pm√(69)\n-------------\n8.\ 7x^2=-21\ \ \ \ /:(-7)\n\nx^2=-3-no\ real\ solutions\n-------------\n$
$9.\ m^2+7=88\ \ \ \ /-7\n\nm^2=88-7\n\nm^2=81\n\nm=\pm√(81)\n\nm=\pm9\n-------------\n10.\ -5x^2=-500\ \ \ \ /:(_5)\n\nx^2=100\n\nx=\pm√(100)\n\nx=\pm10\n-------------\n$
$11.\ -7n^2=-448\ \ \ \ /:(-7)\n\nn^2=64\n\nn=\pm√(64)\n\nn=\pm8\n-------------\n12.\ -2k^2=-162\ \ \ \ /:(-2)\n\nk^2=81\n\nk=\pm√(81)\n\nk=\pm9\n-------------\n$
$13.\ x^2-5=73\ \ \ \ /+5\n\nx^2=78\n\nx=\pm√(78)\n-------------\n14.\ 16n^2=49\ \ \ \ /:16\n\nn^2=(49)/(16)\n\nn=\pm\sqrt(49)/(16)\n\nn=\pm(√(49))/(√(16))\n\nn=\pm(7)/(4)$

How many feet is 43 meters

Answers

43 meters is 137.7 or (if you want to round) it's 138 feet.

The answer to your question is 141.076 feet. Anything else you need?

Chris divided 1/2 pound of nails into 6 small bags. He wants all bags to have equal weight. How much does each bag weigh? A. 1/2 pound.B. 1/3 pound
C. 1/6 pound
D. 1/12 pound

Answers

D, 1/12 pound. A way to think of this is that if there is 1/12 in 6 different bags, you get 6/12, which is equivalent to 1/2

A solid with two parallel and congruent bases cannot be which of the following? A. Cylinder
B. Cube
C. Prism
D. Pyramid

Answers

That answer is pyrimad cuz it has 4 sides and congruent parell 2 sidesHOPE I HELPED?!!!!! If u need more help just contact me

John, Sally, and Natalie would all like to save some money. John decides that itwould be best to save money in a jar in his closet every single month. He decides
to start with $300, and then save $100 each month. Sally has $6000 and decides
to put her money in the bank in an account that has a 7% interest rate that is
compounded annually. Natalie has $5000 and decides to put her money in the
bank in an account that has a 10% interest rate that is compounded continuously.

How much money have after 2 years?

How much money will sally have in 10 years?

What type of exponential model is Natalie’s situation?

Write the model equation for Natalie’s situation

How much money will Natalie have after 2 years?

How much money will Natalie have after 10 years

Answers

Answer:

Part 1) John’s situation is modeled by a linear equation (see the explanation)

Part 2) $y=100x+300$

Part 3) $\$12,300$

Part 4) $\$2,700$

Part 5) Is a exponential growth function

Part 6) $A=6,000(1.07)^(t)$

Part 7) $\$11,802.91$

Part 8) $\$6,869.40$

Part 9) Is a exponential growth function

Part 10) $A=5,000(e)^(0.10t)$ or $A=5,000(1.1052)^(t)$

Part 11) $\$13,591.41$

Part 12) $\$6,107.01$

Part 13) Natalie has the most money after 10 years

Part 14) Sally has the most money after 2 years

Step-by-step explanation:

Part 1) What type of equation models John’s situation?

Let

y ----> the total money saved in a jar

x ---> the time in months

The linear equation in slope intercept form

y=mx+b

The slope is equal to

$m=\$100\ per\ month$

The y-intercept or initial value is

$b=\$300$

$y=100x+300$

therefore

John’s situation is modeled by a linear equation

Part 2) Write the model equation for John’s situation

see part 1)

Part 3) How much money will John have after 10 years?

Remember that

1 year is equal to 12 months

$10\ years=10(12)=120 months$

For x=120 months

substitute in the linear equation

$y=100(120)+300=\$12,300$

Part 4) How much money will John have after 2 years?

Remember that

1 year is equal to 12 months

$2\ years=2(12)=24\ months$

For x=24 months

substitute in the linear equation

$y=100(24)+300=\$2,700$

Part 5) What type of exponential model is Sally’s situation?

we know that

The compound interest formula is equal to

$A=P(1+(r)/(n))^(nt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$P=\$6,000\n r=7\%=0.07\nn=1$

substitute in the formula above

$A=6,000(1+(0.07)/(1))^(1*t)\n A=6,000(1.07)^(t)$

therefore

Is a exponential growth function

Part 6) Write the model equation for Sally’s situation

see the Part 5)

Part 7) How much money will Sally have after 10 years?

For t=10 years

substitute the value of t in the exponential growth function

$A=6,000(1.07)^(10)=\$11,802.91$

Part 8) How much money will Sally have after 2 years?

For t=2 years

substitute the value of t in the exponential growth function

$A=6,000(1.07)^(2)=\$6,869.40$

Part 9) What type of exponential model is Natalie’s situation?

we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^(rt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$P=\$5,000\nr=10\%=0.10$

substitute in the formula above

$A=5,000(e)^(0.10t)$

Applying property of exponents

$A=5,000(1.1052)^(t)$

therefore

Is a exponential growth function

Part 10) Write the model equation for Natalie’s situation

$A=5,000(e)^(0.10t)$ or $A=5,000(1.1052)^(t)$

see Part 9)

Part 11) How much money will Natalie have after 10 years?

For t=10 years

substitute

$A=5,000(e)^(0.10*10)=\$13,591.41$

Part 12) How much money will Natalie have after 2 years?

For t=2 years

substitute

$A=5,000(e)^(0.10*2)=\$6,107.01$

Part 13) Who will have the most money after 10 years?

Compare the final investment after 10 years of John, Sally, and Natalie

Natalie has the most money after 10 years

Part 14) Who will have the most money after 2 years?

Compare the final investment after 2 years of John, Sally, and Natalie

Sally has the most money after 2 years

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