How many tenths are in 1 whole

Answer:

I will like to help you but where is the diagram?

Step-by-step explanation:

Answer:

The pairs of ( x,y) are ( -3 ,16) , ( 0,1) and ( 3,4)

Step-by-step explanation:

y = ( x -1)²

y   = x² - 2 x + 1

 for x = -3

y =( -3)² - 2 × -3 + 1

  = 9 +6 +1

  = 16

so ( x, y) = ( -3 , 16)

for x = 0

y = 0² - 2 ×0 + 1

  = 1

so ( x,y) = ( 0,1)

For x = 3

y = 3² - 2 × 3 +1

   = 9 - 6 +1

   = 4

( x,y) = (3 , 4)

so the pairs of ( x,y) are ( -3 ,16) , ( 0,1) and ( 3,4)

Answer:

Ecuaciones algebraicas. De primer grado o lineales. De segundo grado o cuadráticas...

Ecuaciones trascendentes, cuando involucran funciones no polinómicas, como las funciones trigonométricas, exponenciales, logarítmicas, etc.

Ecuaciones diferenciales. Ordinarias...

Ecuaciones integrales.

Ecuaciones funcionales.

Hope this helps! :)

Here is your equation:

In this equation, you're looking for the value of d alone. That means you would have to move everything next to the variable to the other side. You can do that by doing the opposite of what's being done to it.

In this equation, 5d is being subtracted by 10(-10). The opposite of that is adding 10(+10). You would have to add 10 to both sides, since -10 and +10 cancel out each other.

The first thing you are going to do is add 10 to both sides.

Now you're left with the equation 5d=30. Remember that you're looking for d alone. In the current equation, d is being multiplied by 5(5d ⇒ 5 × d). Again, you're going to do the opposite of what's being done to it. The opposite of multiplying is dividing, therefore, you're going to divide both sides by 5, since the 5 divided by 5 is 1, which cancels out the 5.

Divide both sides by 5.

That means the answer to your equation is d = 6.

Answer:

d = 6

Step-by-step explanation:

Let us follow these steps to make d the subject.

First, add 10 to both sides.

5d - 10 = 20

5d = 10+ 20

5d = 30

Divide both sides by 5.

d = 6