How does the electric potential energy between two charged particles change if one particle's charge is increased by a factor of 2?

Answers

Answer 1

Answer:

Answer:

Magnitude of potential energy is increased by factor "2"

Explanation:

As we know that if two charge particles are placed at some distance "r" from each other then the electrostatic potential energy between two charge particles is given as

$U = (kq_1q_2)/(r)$

now we know that if the charge of one of the charge particle is increased to twice of initial charge then

$U' = (kq_1(2q_2))/(r)$

now we can say from above two equations that

$U' = 2U$

so on increase one of the charge to twice of initial value then the potential energy will become TWICE

Answer 2

Answer: from the formula of electric potential = (1/4πe)*(Qq/r), if one of the charge is doubled, the electric potential energy would be doubled too. Not so sure though, u might wanna double-check with someone else. But hope that helps. :)

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A 1000-kg barge is being towed by means of two horizontal cables. One cable is pulling with a force of 80.0 N in a direction 30.0° west of north. In what direction should the second cable pull so that the barge will accelerate northward, if the force exerted by the cable is 120 N?

Answers

Answer:

θ = 19.47°

Explanation:

given,

mass of the barge = 1000 kg

force applied to pull = 80 N

direction = 30° west to north

force exerted by the cable = 120 N

direction = ?

first cable is pulling

in north direction = 80 cos ∅

= 80 cos 30°

= 69.28 N

in west direction = 80 sin ∅

= 80 sin 30°

= 40 N

the other cable will pull in the opposite direction of west

now,

$120 sin \theta = 40$

$sin \theta = (40)/(120)$

$\theta = sin^(-1){(1)/(3)}$

θ = 19.47°

the direction of the cable will be equal to θ = 19.47°

A ball rolls down an incline with an acceleration of 10 cm/s^2. If it starts with an initial velocity of 0 cm/s and has a velocy of 50 cm/s when it reaches the bottom of the ramp, how long is the ramp?

Answers

Given a = 10 cm/s²
u = 0 cm/s
v = 50 cm/s
we know that
v²=u²+2aS
2500=2×10×S
2500÷20 = S
S= 125 cm
The ramp is 125 cm

Final answer:

The time for the ball to reach the bottom of the ramp is 5 seconds. Using this time value, the acceleration, and the initial velocity, you can calculate the length of the ramp, which is found to be 125 cm.

Explanation:

The question involves the physics principles of kinematics, specifically the concept of acceleration. Given that the initial velocity is 0 cm/s, the final velocity is 50 cm/s, and the acceleration is 10 cm/s^2, you can find the time it took for the ball to reach the bottom using the formula vf=vi+at (Final velocity = initial velocity + acceleration * time). Substituting the given values, you get the equation 50cm/s = 0cm/s + 10cm/s^2 * time, simplifying which gives time = 5 seconds.

To find the length of the ramp, you can use another kinematic equation, d = vit + 0.5at^2 (Distance = initial velocity * time + 0.5 * acceleration * time^2). Substituting the values we know, (initial velocity = 0, acceleration = 10 cm/s^2, time = 5 s), the equation simplifies to d = 0*5 + 0.5*10*5^2 = 0 + 0.5*10*25 = 125 cm. Therefore, the length of the incline or ramp is 125 cm.

Learn more about Kinematics here:

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A 10-meter long ramp has a mechanical advantage of 5. What is the height of the ramp?

Answers

1. If the ramp has a length of 10 and has a mechanical advantage (MA) of 5. Then we need to find the height of the ramp.
Formula:
MA = L / H
Since we already have the mechanical advantage and length, this time we need to find the height .
MA 5 = 10 / h
h = 10 / 5
h = 2 meters

Therefore, the ramp has a length of 10 meters, a height of 2 meters with a mechanical advantage of 5.

Answer:

height=2

Explanation:

MA= input/output

MA= 5

input = 10 (the ramp)

output=x (the height)

5=10/x

x=2

10Two blocks A and B are joined by a string and rest on a frictionless horizontal table. A force a
200N is applied horizontally on block B.
Upload the picture of your answer (Non-anonymous question)* (10 Points)
A
Draw free-body diagrams for both boxes.
Upload filo
B
200 N