a park is 4 times as long as it is wide. if the distance around the park is 12.5 kilometers, what is the area of the park?

Answers

Answer 1
Answer: So, first, what are the two sides?

let's call then x and y

we know that 2(x+y)=12.5 (that's the distance around)

so that means that x+y=6.25 (I just divided both by 2)

now, x=4y (from "4 times as long as it is wide")

so we can substitute:

x+4x=6.25

5x=6.25

x=1.25

so one side, is 1.25 and the other will be 1.25*4=5

and for the area we multiply the two:

1.25*5=6.25 square kilometers, and this is the answer!
Answer 2
Answer:

The Area of the park is 6.25 square kilometers.

  • Let the wide = X
  • The length = 4X (the length is 4 times long as it is wide)

Further Explanation

Therefore, we should have:

To determine the perimeter of the rectangle = 2 x (length + wide)

P = 2 (L + W)

P = 2L + 2W

Recall the distance around the park is 12.5,

Hence,

= 12.5 = 2 (4x) + 2 (x)

= 12.5 = 8x + 2x

= 12.5 = 10x

X = (12.5)/(10)

X = 1.25

To determine the area, the formula for area is (A = W x L)

A = X x (4X)

A = 4X^(2)

A = 4 x (1.25)^(2)

A = 4 x (1.25 x 1.25)

A = 4 x 1.5625

A = 6.25 square kilometers

Thus, the area of the park is 6.25 square kilometers.  

LEARN MORE:

  • A park is 4 times as long as it is wide. if the distance around the park is 12.5 kilometers, what is the area of the park brainly.com/question/768779
  • A park is 4 times as long as it is wide. if the distance around the park is 12.5 kilometers, what is the area of the park  brainly.com/question/286278

KEYWORDS:

  • square kilometers
  • a park is 4 times
  • wide
  • area of a rectangle
  • perimeter of a rectangle
  • area of the park

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 2.755778 thats the answer have nice day :)

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Answers

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Answers

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Find the average rate of change for f(x) = x2 + 9x + 18 from x = 10 to x = 20.A) 33
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D) 41

Answers

Answer:

The average rate of change is 39

Step-by-step explanation:

First, plug x=10 and x=20 into the formula:  

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please mark as Brainliest

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AND
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Answers

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