MATHEMATICS HIGH SCHOOL

What is the volume of a four- sided pyramid with base edge of 5 ft and h = 4 ft.

Answers

Answer 1

Answer: V = $(5^(2) * 4)/3$ = 100/3;

Answer 2

Answer:

Answer:

Step-by-step explanation:

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If r and s can be any integers such that s > 10 and 2r + s = 15, which of the following is the solution set for r ?

Answers

R = -2
2x-2=-4
S = 19
This may be a possible answer

Colin took out a loan with a principal of $32,800. After five years, the interest and principal totaled $48,872. If Colin made monthly payments of $816 for five years until the loan was paid off, how much did Colin pay in service charges?

Answers

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Below are the choices:

a.
$16,072
b.
$88
c.
$16,160
d.
$163

816 * 5 * 12= 48960

If the P and I totaled 48872, then...
48960 - 48872= 88

The service charges were $88 B.

Answer:

B. 88!!!

Step-by-step explanation:

Solve for x 7x-3=5x+5=

Answers

The value of x in the expression 7x-3=5x+5 is 4

Given

7x-3=5x+5

Here,

The equation is linear in variable x .

7x-3=5x+5

7x - 5x - 3 = 5

2x-3=5

2x = 5 + 3

2x=8

x = 8/2

x=4

Thus the value of x is 4 .

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Answer:

x=4

Step-by-step explanation:

7x-3=5x+5

2x-3=5

2x=8

x=4

Math help please!!!
**check picture below**

Answers

Simple...

$(3x y^(3) )(2 x^(3)y)$

3*2=6

$x* x^(3)= x^(4)$ (Exponents "multiplied" are added)

$y^(3) *y= y^(4)$

Making it...

$6 x^(4)y ^(4)$

Thus, the answer to your first question.

The Second One....

$(x^(2) -2x-2)*( x^(2) +2x+3)$

It looks hard, but it's not...break it down..

$x^(2) * x^(2) = x^(4)$

$x^(2) *-2x=-2 x^(3)$

$x^(2) *2x=2 x^(3)$

$x^(2) *-2=-2 x^(2)$

$-2x*2x=-4 x^(2)$

$x^(2) *3=3 x^(2)$

-2*2x=-4x

-2x*3=-6x

-2*3=-6

Now..FINALLY...add it up..

Making the answer to your second equation...

$x^(4) -2 x^(3) +2x ^(3) -6x ^(2) +3 x^(2) -10x-6$

$x^(4) -3x ^(2)-10x-6.$

(5x + 6x3 + 2x) - (3x - 2x3 - 7x2) is equivalent to:8x3 + 12x2 - X
B
4x3 -- 5x2 - x
C
-4x3 + x2 + 6x
2x3 + 4x2 -- 5x

Answers

Answer:

A- 8x^3 + 12x^2 - x

Step-by-step explanation:

The symbol ^ with a 2 is squared and ^ with 3 means cubed.

1. Add a 1 before the parenthesis on both sides. Now, the equation should look like 1(5x^2 + 6x^3 + 2x) -1(3x - 2x^3 - 7x^2).

2. Now we should distribute. 1 × 5x^2 + 1 × 6x^3 + 1 × 2x -1 × 3x + -1 × -2x^3 + -1 × -7x^2.

3. Now the equation should be simplified.

1 × 5x^2 = 5x^2

1 × 6x^3 = 6x^3

1 × 2x = 2x

-1 × 3x = -3x

-1 × -2x^3 + -1 = 2x^3 -1. In this equation, there is a +- sign together, which is the same as a - sign.

-1× -7x^2 = 7x^2

4. The new equation is 5x^2 + 6x^3 + 2x - 3x + 2x^3 - 1 + 7x^2

5. Now you can combine the like terms. 5x^2 and 7x^2 can be added, so 5x^2 + 7x^2 is equal to 12x^2. Also, 6x^3 and 2x^3 can be added, so 6x^3 + 2x^3 is equal to 8x^3. Lastly, 2x and -3x can be combined, so 2x - 3x is equal to -1x or -x.

6. So, the simplified equation is 12x^2 + 8x^3 -x. You can also write it as 8x^3 + 12x^2 - x. So, A is the answer.

F c(x) = 4x – 2 and d(x) = x2 + 5x, what is (C o D)(x)?A) 4x^3 + 18x^2 – 10x
B) x^2 + 9x – 2
C) 16x^2 + 4x – 6
D) 4x^2 + 20x – 2

Answers

The value for the compositefunction is 4x² + 20x - 2.

Option D is the correct answer.

What is a function?

A function has an input and an output.

A function can be one-to-one or onto one.

It simply indicated the relationships between the input and the output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

To find (C o D)(x), we need to substitute d(x) into c(x) and simplify the resulting expression.

First, we have:

C(D(x)) = 4D(x) - 2

Next, we substitute d(x) for x in the expression for D(x):

D(x) = x² + 5x

So,

C(D(x)) = 4(x² + 5x) - 2

Simplifying, we get:

C(D(x)) = 4x² + 20x - 2

Therefore,

The value for the compositefunction is 4x² + 20x - 2.

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$\bf \begin{cases}c(x)=4x-2\n\nd(x)=x^2+5x\end{cases}\qquad thus\n\n\n(c\circ d)(x)\implies \begin{array}{llll}c(x)=&4x-2\n\nc[\ d(x)\ ]=&4(dx)-2\n\nc[\ \boxed{x^2+5x}\ ]= &4(\boxed{x^2+5x})-2\end{array}$

distribute and simplify

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