What is 2/9 as a decimal ?

Answers

Answer 1

Answer: 0.22222 so on

.22222 so on

this ur answer

Answer 2

Answer: to find the decimal of 2/9 , u have to do 2 divided by 9 which equals 0.22222222222

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you throw a ball upward. its height h in feet after t seconds can be modeled by the function h=-16t^2+30t+6.after how many seconds will it hit the ground

Answers

When the ball hit the ground, the height will be equal to "0".
h=0
Then:

-16t²+30t+6=0

we have to solve this square equation:

t=[-30⁺₋√(900+384)] / (-32)
t=(-30⁺₋√1284)/(-32)
we have two solutions:
t₁=(-30-√1284)/(-32)=2.06
t₂=(-30+√1284)/(-32)=-0.18 This solution is not valid.

Answer: 2.06 seconds.
t

Write 1 2/3 as the sum of a whole number and two fractions that have the same denominator.

Answers

1+1/3+1/3 because 1/3 and 1/3 have the same denominator.

How many 2/5 are in 1

Answers

Steps:
1. If you do 2/5 + 2/5= 4/5. 4/5 would be the closest you could get to 1
2. So, you only have 1/5 left
3. That means that 2/5 can only go into 1 two times
4. Your answer is that there are two 2/5 in 1

13. Line m has no y-intercept, and its x-intercept is (-5, 0). Line n has no x-intercept,and its y-intercept is (0, 3).
Write the equation of line m.
Write the equation of line n.

Answers

Line m equation is $x+5 = 0$ .

Line n equation is $y+3 = 0$ .

Step-by-step explanation:

Here , we have Line m has no y-intercept, and its x-intercept is (-5, 0). Line n has no x-intercept, and its y-intercept is (0, 3). Let's find out equation of both line step by step:

Equation of line m:

Line m has no y-intercept , that means line is never intersecting y-axis which is only possible when line is parallel to y-axis , also this line have x-intercept as (-5,0) i.e. cuts x-axis at x = -5 .

⇒ $x = -5$

⇒ $x+5 = 0$

∴ Line m equation is $x+5 = 0$ .

Equation of line n:

Line n has no x-intercept , that means line is never intersecting x-axis which is only possible when line is parallel to x-axis , also this line have y-intercept as (0,3) i.e. cuts y-axis at y = 3 .

⇒ $y = -3$

⇒ $y+3 = 0$

∴ Line n equation is $y+3 = 0$ .

A survey was conducted to determine the average age at which college seniors hope to retire in a simple random sample of 101 seniors, 55 was theaverage desired retirement age, with a standard deviation of 3.4 years. A 96% confidence interval for desired retirement age of all college students is:
54.30 to 55.70
54.55 to 55.45
54.58 to 55.42
54 60 to 55.40

Answers

Answer:

96% confidence interval for desired retirement age of all college students is [54.30 , 55.70].

Step-by-step explanation:

We are given that a survey was conducted to determine the average age at which college seniors hope to retire in a simple random sample of 101 seniors, 55 was the average desired retirement age, with a standard deviation of 3.4 years.

Firstly, the Pivotal quantity for 96% confidence interval for the population mean is given by;

P.Q. = $(\bar X-\mu)/((s)/(√(n) ) )$ ~ $t_n_-_1$

where, $\bar X$ = sample average desired retirement age = 55 years

$\sigma$ = sample standard deviation = 3.4 years

n = sample of seniors = 101

$\mu$ = true mean retirement age of all college students

Here for constructing 96% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

So, 96% confidence interval for the population mean, $\mu$ is ;

P(-2.114 < $t_1_0_0$ < 2.114) = 0.96 {As the critical value of t at 100 degree

of freedom are -2.114 & 2.114 with P = 2%}

P(-2.114 < $(\bar X-\mu)/((s)/(√(n) ) )$ < 2.114) = 0.96

P( $-2.114 * {(s)/(√(n) ) }$ < ${\bar X-\mu}$ < $2.114 * {(s)/(√(n) ) }$ ) = 0.96

P( $\bar X-2.114 * {(s)/(√(n) ) }$ < $\mu$ < $\bar X+2.114 * {(s)/(√(n) ) }$ ) = 0.96

96% confidence interval for $\mu$ = [ $\bar X-2.114 * {(s)/(√(n) ) }$ , $\bar X+2.114 * {(s)/(√(n) ) }$ ]

= [ $55-2.114 * {(3.4)/(√(101) ) }$ , $55+2.114 * {(3.4)/(√(101) ) }$ ]

= [54.30 , 55.70]

Therefore, 96% confidence interval for desired retirement age of all college students is [54.30 , 55.70].

8x+4y=-20 and -4x-8y=-20 solve each system by substitution

Answers

8x + 4y = -20
4y = -20 - 8x
y = -5 -2x

-4x - 8y = -20
-4x - 8(-5-2x) = -20
-4x + 40 + 16x = -20
12x = -60
x = -5

8(-5) + 4y = -20
-40 + 4y = -20
4y = 20
y = 5

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