A 12 volt car battery produces more current than a 1.5 volt battery for a TV remote because...A. the tv remote has more kinetic energy.
B. the tv remote has a greater difference in electric potential energy.
C. the car bettery has a greater difference in electric potential energy.
D. the car bettery has more kinetic energy.

Answers

Answer 1

Answer:
This question is loaded with misleading, marginally meaningful phrases.

A 12V battery produces more current than a 1.5V battery produces,
through the same device, because the potential difference between
the terminals of the 12V battery is 8 times the potential difference
between the terminals of the 1.5V battery.

Of the choices offered, choice 'C' is the closest. But it should say
"electrical potential", NOT "potential energy".

Answer 2

Answer:

Final answer:

A 12-volt car battery produces more current than a 1.5-volt TV remote battery because it has a greater difference in electric potential energy, resulting in a larger 'push' of electrons and therefore a larger current.

Explanation:

A 12-volt car battery produces more current than a 1.5 volt battery for a TV remote because the car battery has a greater difference in electric potential energy. The electric potential energy is related to the voltage of the battery, or the 'push' it provides to move electrons through a circuit. A higher voltage means a greater 'push' and thus, more current. This is evidenced by the fact that car batteries are designed to start cars, which requires a larger current than operating a TV remote.

Learn more about Electric Potential Energy here:

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Special relativity questions?1.) A rocket is moving at 1/4 the speed of light relative to Earth. At the center of this rocket, a light suddenly flashes. To an observer at rest on Earth
a. the light will reach the front of the rocket after it reaches the back of the rocket.
b. the light will reach the front of the rocket at the same instant that it reaches the back of the rocket.
c. the light will reach the front of the rocket before it reaches the back of the rocket. 2.) A rocket is moving at 1/4 the speed of light relative to Earth. At the center of this rocket, a light suddenly flashes. To an observer at rest in the rocket
a. the light will reach the front of the rocket before it reaches the back of the rocket.
b. the light will reach the front of the rocket at the same instant that it reaches the back of the rocket.
c. the light will reach the front of the rocket after it reaches the back of the rocket. 3.) An astronaut in an inertial reference frame measures a time interval Δt between her heartbeats. What will observers in all other inertial reference frames measure for the time interval between her heartbeats?
a. Δt
b. less than Δt
c. more thanΔt
d. The answer depends on whether they are moving toward her or away from her. 4.) You are a passenger on a spaceship. As the speed of the spaceship increases, you would observe that
a. the length of your spaceship is getting shorter.
b. the length of your spaceship is not changing.
c. the length of your spaceship is getting longer. 5.) A star is moving towards the earth with a speed at 90% the speed of light. It emits light, which moves away from the star at the speed of light. Relative to us on earth, what is the speed of the light moving toward us from the star?
a. 0.90c
b. 1.9c
c. 1.20c
d. 1.1c e,) c

Answers

The right answer for the question that is being asked and shown above is that:
(1) b. the light will reach the front of the rocket at the same instant that it reaches the back of the rocket.
(2) a. the light will reach the front of the rocket before it reaches the back of the rocket.
(3) b. less than Δt
(4) c. the length of your spaceship is getting longer.
(5) c. 1.20c

How to generate electricity from biogas?

Answers

The same way as electricity is generated from any other gas:

-- Burn the gas.
-- Use the heat to boil water.
-- Pipe the steam through the fan of a turbine.
-- Use the rotation of the turbine to spin an electric-power generator.

Some hypothetical alloy is composed of 12.5 wt% of metal A and 87.5 wt% of metal B. If the densities of metals A and B are 4.27 and 6.35 g/cm3, respectively, and their respective atomic weights are 61.4 and 125.7 g/mol, determine whether the crystal structure for this alloy is simple cubic, face-centered cubic, or body-centered cubic. Assume a unit cell edge length of 0.395 nm.

Answers

The number of atoms in the unit cell of hypothetical alloy composed of metal A and B is 2 so the crystal structure is body-centered cubic.

What is crystal structure?

The crystal structure is the order of the atom arrangement in a repeating way. types of crystal structure are-

Simple cubic-In this arrangement, one atom is placed at each corner of the unit cell.
Face-centered cubic-In this arrangement, one atom is placed at each corner of the unit cell and one atom is placed at each face of the unit cell.
Body-centered cubic-In this arrangement, one atom is placed at each corner of the unit cell and one atom is placed at center of the unit cell.

Number of atom can be find out with the following formula,

$n=(N\rho)/(m)[\tex]Here, (m) is the mass of the object and (N) is Avogadro's number.Given information-Hypothetical alloy is composed with metal A of 12.5 wt%.Hypothetical alloy is composed with metal B of 87.5 wt%.Densities of metals A and B are 4.27 and 6.35 g/cm 3,Atomic weights of A and B are 61.4and 125.7 g/mol,The density of the alloy is,[tex]\rho=(1)/((12.5)/(4.27)+(87.5)/(6.35))*100=5.98[\tex]Similarly the mass of the alloy is,[tex]m=(1)/((12.5)/(61.4)+(87.5)/(125.7))*100=111.15[\tex]As the mass and the density of the alloy has been obtained and the Avogadro's number is 6.023*10²³.Put the value in the above equation to find the number of atom, we get,[tex]n=2$

Thus the number of atoms in the unit cell is 2. The crystal structure is body-centered cubic.

Learn more about the crystal structure here;

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Answer:

The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.

Explanation:

Given that,

Weight of metal A = 12.5%

Weight of metal B = 87.5%

Length of unit cell = 0.395 nm

Density of A = 4.27 g/cm³

Density of B= 6.35 g/cm³

Weight of A = 61.4 g/mol

Weight of B = 125.7 g/mol

We need to calculate the density of the alloy

Using formula of density

$\rho=n*(m)/(V_(c)* N_(A))$

$n=(\rho*V_(c)* N)/(m)$ ....(I)

Where, n = number of atoms per unit cells

m = Mass of the alloy

V=Volume of the unit cell

N = Avogadro number

We calculate the density of alloy

$\rho=(1)/((12.5)/(4.27)+(87.5)/(6.35))*100$

$\rho=5.98$

We calculate the mass of the alloy

$m=(1)/((12.5)/(61.4)+(87.5)/(125.7))*100$

$m=111.15$

Put the value into the equation (I)

$n=(5.9855*(0.395*10^(-9)*10^(2))^3*6.023*10^(23))/(111.15)$

$n=1.99\approx 2\ atoms/cell$

Hence, The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.

What is the working procedure of electric geyser

Answers

Working of Electric Geyser:
the phenomenon which occurs is only the transfer of electric energy into the heat energy...
the water enters through the input and then it is passed into a container having alloy coil which is also covered by conductor of heat but this conductor cannot pass electricity into water but only heat...
then water is heated over there and comes out through outlet...

There is a copper coil present in the electric geyser which gets hot when electricity is passed through it . This rod makes the water in the geyser hot .

At what location in a circuit is the electrical potential energy the greatest

Answers

It's not the potential energy. It's just the potential.

It's greatest at the positive terminal of the battery or power supply.

A good sign that cardiovascular exercise is occurring is that you _____.

Answers

Answer: are breathing much faster

Explanation:

Exercise is a physical activity which increases the rate of respiratory and cardiovascular activity of the body. The cardiovascular exercise is likely to increase the rate at which the heart pumps blood as the body faces the scarcity of oxygen in the muscles which conducts the exercise. This increases rate of breathing so as to acquire more amount of oxygen. The oxygenated blood is pumped by the heart to all the parts of the body.

Are breathing hard. This is because cardiovascular exercise makes the heart beat faster which in turn creates a need for more air.

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