A function f (x)=-8x^2. What is f (-3)?

Answers

Answer 1

Answer: f(x) = -8x²

To find the value of f(-3), put -3 in place of 'x' in the definition of the function.

f(-3) = -8(-3)²

f(-3) = -8(9) = -72

Answer 2

Answer: f(x)= -8x²

f(-3)= -8* (-3)²

f(-3)= -8 * 9

f(-3)= -72

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A rectangle has a length of 4 2/5 cm and a width of 1 3/10 cm. What is the area of the rectangle?

Answers

If you would like to know what is the area of the rectangle, you can calculate this using the following steps:

the area = a length * a width
x = 4 2/5 cm * 1 3/10 cm
x = 22/5 * 13/10
x = 143/25 = 5 18/25 square cm

The correct result would be 5 18/25 square cm.

Which is a factor of x2 + 8x – 48?

Answers

so x^2+8x-48
it can be written in the form
ax^2+bx+c

so since the 'a' term=1 we want it in form
(x +/- something1 )(x +/- something2 )
so basically, something1 times something 2=c and something 1+something 2=b

c=-48
b=8

factor -48 and fiind what 2 factors add to 8 (obviously one has to be positive and is 8 more than the negative [negative is smaller])
-48=
-1 times 48 no
-2 times 24 no
-3 times 16 no
-4 times 12 yes
-4+12=8

therefor it is
(x-4)(x+12) or (x+12)(x-4)

so the answer would be the one with either (x+12) or (x-4) (since you didn't include answer choices)

(x+12) or (x-4) would be the right choice

this trinomial factored is:
(x + 12)(x - 4)
either of these would be considered a factor.

1. Discuss the differences between the measurement of the surface area and the measurement of the volume of a right rectangular prism. Include the following topics in your discussion. (a) Description of regions that are measured (b) Units for each type of measure and why the units are different (c) Examples of when you would want to measure for each type of measure

Answers

surface area=area needed to wrap a box
volume=amount of space in the box

surface area=2hl+2hw+2wl=2(hl+hw+wl)
volume=hlw
h=height
l=legnth
w=width

a. surface area is the outside area. lets say you have a cardboard cube and cut it on all the corners and edges so you ended up with 6 squares, the total areas of those squares is the surface area of the cube
volume is how much stuff can be put into the cube, we measure how many 1 by 1 by 1 cubes can fit into the object or how much water can fit in the cube

b. surface area is 2 dimentional since it is area and can be folded flat so the units would be square feet or square inches (ft^2, in^2)
volume is 3 dimentional since it is legnth width and height so it would be cubic foot, cubic inch (in^3, ft^3)

c. surface area=wrapping paper, wrapping stuff, painting an object
volume=how much water can fit in pool, how much punch to put in the jar to fill it up, which water bottle to bring so you have enough water

surface area=area needed to wrap a box

volume=amount of space in the box

surface area=2hl+2hw+2wl=2(hl+hw+wl)

volume=hlw

h=height

l=legnth

w=width

a. surface area is the outside area. lets say you have a cardboard cube and cut it on all the corners and edges so you ended up with 6 squares, the total areas of those squares is the surface area of the cube

volume is how much stuff can be put into the cube, we measure how many 1 by 1 by 1 cubes can fit into the object or how much water can fit in the cube

b. surface area is 2 dimentional since it is area and can be folded flat so the units would be square feet or square inches (ft^2, in^2)

volume is 3 dimentional since it is legnth width and height so it would be cubic foot, cubic inch (in^3, ft^3)

c. surface area=wrapping paper, wrapping stuff, painting an object

volume=how much water can fit in pool, how much punch to put in the jar to fill it up, which water bottle to bring so you have enough water

Taylor graphs the system below on her graphing calculator and decides that f(x)=g(x) at x=0, x=1, and x=3. Provide Taylor some feedback that explains which part of her answer is incorrect and why it is incorrect. f(x)=2x+1g(x)=2x^2+1

Answers

Answer:

$f(x)=g(x)$ at x= 0 and x= 1 and not at x= 3.

Step-by-step explanation:

We have the functions, $f(x)=2x+1$ and $g(x)=2x^2+1$ .

It is given that,

At x=0, x=1, and x=3, $f(x)=g(x)$

i.e. $2x+1=2x^2+1$

i.e. $2x^2-2x=0$

i.e. $2x(x-1)=0$

i.e. x= 0 and (x-1)= 0

i.e. x= 0 and x= 1.

Also, after plotting the graphs of both the functions, we see their intersection point are (0,1) and (1,3).

Thus, we get that $f(x)=g(x)$ at x= 0 and x= 1 and not at x= 3.

There are 3 times as many pears are oranges. If a group of children receive 5 oranges each,there will be no left over.If the same group of children receive 8 oranges each, there will be 21 pears left over. How many oranges are there?

Answers

There are 15 oranges

Solution:

Let "x" be the number of oranges

Let "y" be the number of pears

Let "c" be the number of children

There are 3 times as many pears are oranges

Number of pears = 3 times the number of oranges

y = 3x -------- eqn 1

If a group of children receive 5 oranges each, there will be no left over

So, "c" children receives 5 oranges each, there will be no left over

number of oranges = 5(number of children)

x = 5c ------- eqn 2

If the same group of children receive 8 oranges each, there will be 21 pears left over

number of pears = 8 oranges(number of children) + 21

y = 8c + 21

Substitute eqn 1

3x = 8c + 21 ---- eqn 3

Substitute eqn 2

3(5c) = 8c + 21

15c - 8c = 21

7c = 21

c = 3

Substitute c = 3 in eqn 2

x = 5(3)

x = 15

Thus there are 15 oranges

Answer:

15 orangs

Step-by-step explanation:

There are 15 oranges

Solution:

Let "x" be the number of oranges

Let "y" be the number of pears

Let "c" be the number of children

There are 3 times as many pears are oranges

Number of pears = 3 times the number of oranges

y = 3x -------- eqn 1

If a group of children receive 5 oranges each, there will be no left over

So, "c" children receives 5 oranges each, there will be no left over

number of oranges = 5(number of children)

x = 5c ------- eqn 2

If the same group of children receive 8 oranges each, there will be 21 pears left over

number of pears = 8 oranges(number of children) + 21

y = 8c + 21

Substitute eqn 1

3x = 8c + 21 ---- eqn 3

Substitute eqn 2

3(5c) = 8c + 21

15c - 8c = 21

7c = 21

c = 3

Substitute c = 3 in eqn 2

x = 5(3)

x = 15

Thus there are 15 oranges

Write the equation a. a vertical line that passes through the point (2,-6)

b. the y axis

c. a horizontal line that passes through the point (1,4)

d. the x axis

Answers

$a)\ x=2\n\nb)\ x=0\n\nc)\ y=4\n\nd)\ y=0$

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