Which choice is equivalent to the expression below?6√7 - 5X√7 - X√7

A.-2√7
B. 0
C.-X^2
D.6V7-6X√7

Answers

Answer 1
Answer: 6\sqrt7-5x\sqrt7-x\sqrt7=6\sqrt7-6x\sqrt7\n\nAnswer:D.
Answer 2
Answer: 6\sqrt7 - 5x\sqrt7 - x\sqrt7=\n 6\sqrt7-6x\sqrt7 \Rightarrow D

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Solve the following system of equation graphically 2x+y=-1 and x+2y=4

Answers

As 2x + y = -1

Then,

y = - 1 - 2x

We can to replace on the bellow equation.

x + 2y = 4

x + 2.( -1 -2x) = 4

Doing the distributive

x + 2.(-1) + 2.(-2x) = 4

x -2 -4x = 4

-3x -2 = 4

-3x = 4 + 2

-3x = 6

x = 6/-3

x = -2
________________

Then, the value of y will be:

y = -1 -2x

y = -1 -2.(-2)

y = -1 + 4

y = 3

If ABC ~ DEC, solve for x. The image is not drawn to scale.A.
x = 2
B.
x = 3
C.
x = 4
D.
x = 13

Answers

Answer: A.    x = 2

Step-by-step explanation:

In the given picture we have \triangle{ABC}\sim\triangle{DEC}

Since, we know that the corresponding sides in similar triangles are in proportion.

Therefore, we have

(CD)/(AC)=(CE)/(BC)\n\n\Rightarrow(8+x)/(6)=(19-2x)/(11-x)\n\n\Rightarrow\ (11-x)(8+x)=6(19-2x)\n\n\Rightarrow\ 88 + 3x -x^2=114-12x\n\n\Rightarrow x^2-15x+26=0\n\n\Rightarrow\ (x-13)(x-2)=0\n\n\Rightarrow\ x=13,2

But x can not be 13 because BC=11-13=-2, which is not possible.

Therefore, the value of  x=2.

If\ \Delta ABC\sim\Delta DEC\ then:\n\n(19-2x)/(11-x)=(8+x)/(6)\ where\ x\in(-8;\ 11)\ \ \ |cross\ multiply\n\n(11-x)(8+x)=6(19-2x)\n11(8)+11(x)-x(8)-x(x)=6(19)+6(-2x)\n88+11x-8x-x^2=114-12x\n-x^2+3x+88=114-12x\ \ \ |subtract\ 114\ from\ both\ sides\n-x^2+3x-26=-12x\ \ \ \ \ |add\ 12x\ to\ both\ sides\n-x^2+15x-26=0\ \ \ \ |change\ signs\nx^2-15x+26=0\nx^2-2x-13x+26=0\nx(x-2)-13(x-2)=0\n(x-2)(x-13)=0\iff x-2=0\ or\ x-13=0\n\nx=2\in(-8;\ 11)\ or\ x=13\notin(-8;\ 11)\n\nAnswer:\boxed{\boxed{A.\ x=2}}

The graph of the following system of equations is (4 points)-2x + y = 3
4x + 2y = 2

a. overlapping lines
b. parallel lines
c. intersecting lines

Answers

\left\{\begin{array}{ccc}-2x+y=3\n4x+2y=2&|divide\ both\ sides\ by\ 2\end{array}\right\n\left\{\begin{array}{ccc}-2x+y=3&|add\ (-2x)\ to\ both\ sides\n2x+y=1&|subtract\ 2x\ from\ both\ sides\end{array}\right\n\left\{\begin{array}{ccc}y=2x+3\ny=-2x+1\end{array}\right\Rightarrow\ the\ slope  \left\{\begin{array}{ccc}m=2\nm=-2\end{array}\right\ |different\n\nConclusion:\ \boxed{\boxed{C}\ intersecting\ lines}
-2x + 1y = 3 ⇒ 4x - 2y = -6
 4x + 2y = 2 ⇒ 4x + 2y = 2
                               -4y = -8
                                -4     -4
                                  y = 2
                      4x + 2(2) = 2
                          4x + 4 = 2
                                 -4  -4
                                4x = -2
                                 4      4
                                 x = -1/2
                             (x, y) = (-1/2, 2)
The answer to the problem is C. intersecting lines.

(2a2 + a + 3) ÷ (a - 1)

Answers

Final answer is: 5a+3/a-1
Answer: 5a+3/a-1

Key: “/“ is a fraction bar
Key: 5a+3 is the numerator
Key: a-1 is the denominator

Hope this helps! <3

Jorge’s monthly bill from his Internet service provider was $25. The service provider charges a base rate of $15 per month plus $1 for each hour that the service is used. Find the number of hours that Jorge was charged for that month.

Answers

Answer:

10 hours for the month

Step-by-step explanation:

What you know: The total amount Jorge was charged for the month was $25

The base rate is $15

He gets charged $1 per each hour

Setting it up:

15+1h=25

(the 15 is the base rate, plus the 1 dollar per hour (h) which both add to the total of 25 dollars for the month)

Subtract 15 from both sides of the equation to get your variable by itself

1h=10

then divide the 1 on both sides to get h (hours) by itself

h=10

And there's your answer, 10 is the number of hours that Jorge was charged for the month

Hopefully this helped :))

Answer:

10

Step-by-step explanation:

$25 - $15 = $10

and its $1 per hour so the answer is 10hrs

Can y’all help me here ?

Answers

Answer:

109

Step-by-step explanation:

3^2=9   -10^2=100