Which choice is equivalent to the expression below?√12-√27+√75

A.21√3
B.9√3
C.5√3
D.4√3

Answers

Answer 1
Answer: √(12) - √(27) + √(75) = √(4*3) - √(9*3) + √(25*3) = \n\n=2√( 3) -3√( 3) + 5√( 3) = 4 \sqrt3}

Answer : \ \ D. \ \ 4 √(3)
Answer 2
Answer: √(12)-√(27)+√(75)=√(4\cdot3)-√(9\cdot3)+√(25\cdot3)\n\n=\sqrt4\cdot\sqrt3-\sqrt9\cdot\sqrt3+√(25)\cdot\sqrt3=2\sqrt3-3\sqrt3+5\sqrt3=4\sqrt3\n\nAnswer:D.

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2.8 MM because it is probably an estimate because nothing is perfect if you zoom in close enough!

Your Mum has saved £12,000 and has agreed to give you a share. Would you rather have 1 5 or 1 10

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I guess it's 1/10 becuase you guys said it so.

Discriminant of 9x^2+12x+4=0

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the\ discriminant\ of\ ax^2+bx+c=0:\ \ \ \ \Delta=b^2-4\cdot b\cdot c \n---------------------------\n9x^2+12x+4=0\ \ \ \Rightarrow\ \ \ \Delta=12^2-4\cdot9\cdot4=144-144=0\n\n\Delta=0\ \ \ \Rightarrow\ \ \ x_0=- (b)/(2a) =- (12)/(2\cdot9) =- (2\cdot2\cdot3)/(2\cdot3\cdot3)= - (2)/(3) \n\nAns.\ The\ discriminant\ is\ \Delta=0
9x^2+12x+4=0\n\n(3x)^2+2\cdot3x\cdot2+2^2=0\n\n(3x+2)^2=0\iff3x+2=0\n\n3x=-2\ \ \ /:3\n\nx=-(2)/(3)\n\n-------------------------------\n\n(a+b)^2=a^2+2ab+b^2

Math help pleaseeeeee

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