Simon Whitfield Victoria, British Columbia, won the men's triathlon at the Sydney Olympics. The race consisted of 1.5 km swim in Sydney harbour, a 40 km bike ride, and a 10km run. A) what percent is each component ?
B) what percent of the race distance is spent on land?
(P.s all these questions are from a text book and are question I don't understand, so pleases explain your answer.)
:)
Answers
Total triathlon distance →1.5 km + 40km + 10 km = 51.5 km
So 51.5 km represents 100% of distance covered.
The % of each component = (distance of component/Total distance) multiplied by 100% so :
% of swim → (1.5 / 51.5) × 100 → 0.029 × 100 = 2.9%
% of bike ride → (40 / 51.5) × 100 →0.776 × 100 = 77.6%
% of run → (10 / 51.5) × 100 → 0.194 × 100 = 19.4%
Percentage spent on land will be
(40 km bike ride + 10 km run / Total triathlon distance) multiplied by 100%
(50 / 51.5) × 100 → 0.970 ×100 = 97%
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The image is attached.
Answer:
x = 16°
Step-by-step explanation:
Segment AB, segment DC and segment EC all intersect at point C.
Here, we are told angle DCE measures 148°.
This is a semi-circle, and the total angle of a semi-circle is 180°.
Which means, x+x+148 = 180
Solving for x, we have:
x+x+148 = 180
2x + 148 = 180
2x = 180 - 148
2x = 32
x = 16°
The value of x is 16°
Final answer:
To find the value of x, we need to deduce the measurements of angles formed by the intersecting segments. By applying the properties of angles in triangles and parallel lines, we can determine that x equals 32 degrees.
Explanation:
Let's name the point of intersection as M. Since segments AB, DC, and EC intersect at point C, it means that point C is common to all three segments.
Given that angle DCE measures 148 degrees, it means that angle DCM (formed by segments DC and EC) is also 148 degrees. We know that the sum of angles in a triangle is 180 degrees.
Therefore, angle CMD (formed by segments DC and AB) is equal to 180 - 148 = 32 degrees. Since segments DC and AB are parallel, angle CMD is also equal to angle ACB.
Hence, the value of x is 32 degrees.
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