MATHEMATICS HIGH SCHOOL

Use a calculator to find each answer. Round to the nearest tenth.1.) 8392-(530+239)
2.) (984.2 - 845) ÷5
3.) (1000÷14.6) +8.4
4.) (8392-530) + 539

Answers

Answer 1
Answer: 7623, 27.8, 76.9, and 8401 it is really simple just use a calculator........

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What is 15 - 7 x 2+ 2 to the 3rd power
A survey of 80 students found that 24 students both play in the band and play a sport. But 22 students are not in band and do not play a sport. There are 48 students in the band. If being in band is the row variable and playing sports is the column variable, fill in the labels in the table. A 4-column table with 3 rows. Column 1 has entries in band, not in band, total. Column 2 is labeled play a sport with entries a, d, g. Column 3 is labeled do not play a sport with entries b, e, h. Column 4 is labeled total with entries c, f, i. Which of the following correctly represents the given data in the problem?A: a = 24, g = 48, h = 22, i = 80 B: a = 22, c = 80, d = 24, i = 48 C: a = 24, b = 48, c = 22, i = 48 D: a = 24, c = 48, e = 22, i = 80
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How do you graph the Quadratic Function of y=x-squared - 4

Answers

y = (x + 2)(x - 2)
y = x(x - 2) + 2(x - 2)
y = x(x) - x(2) + 2(x) - 2(2)
y = x² - 2x + 2x - 4
y = x² - 4

What are the possible values of x in 6x^2 + 432 = 0

Answers

Answer:

x = ±6i sqrt(2)

Step-by-step explanation:

6x^2 + 432 = 0

Subtract 432 from each side

6x^2 =- 432

Divide by 6

6x^2 /6 =- 432/6

x^2 =-72

Take the square root of each side

sqrt(x^2) = ±sqrt( -72)

x = ±sqrt(-1) sqrt(2*36)

We know the square root of -1 = i

x = ±i sqrt(2*36)

x = ±i sqrt(36) sqrt(2)

x = ±6i sqrt(2)

I need help solving 8g+10=35+3g. Please help!!

Answers

Answer:

g = 5

Step-by-step explanation:

Step 1: Write out equation

8g + 10 = 35 + 3g

Step 2: Subtract 3g on both sides

5g + 10 = 35

Step 3: Subtract 10 on both sides

5g = 25

Step 4: Divide both sides by 5

g = 5

(3x-8)(2xsquared4x-9) multiply and write the result in descending order

Answers

Hello there, you can proceed with the multiplication of these factors using the FOIL method (which stands for first, outer, inner and last) multiply I assume that by descending order, you mean by decreasing power. If it were so, the answer is 6(x^3)12(x^2)-16(x^2)32x-27x+72. 

PLEASE HELP!!! needs to be answered in sentaces(01.07 HC)

Michael and Derrick each completed a separate proof to show that corresponding angles AKG and ELK are congruent. Who completed the proof incorrectly? Explain.

Line AB is parallel to EF, transversal GJ crosses line AB at K and crosses line EF at L.

Michael's Proof


Statement Justification
1. line AB ∥ line EF with transversal segment GJ 1. Given
2. angle AKG is congruent to angle AKL 2. Vertical Angles Theorem
3. angle BKL is congruent to angle ELK 3. Alternate Interior Angles Theorem
4. angle AKG is congruent to angle ELK 4. Transitive Property


Derrick's Proof

Statement Justification
1. line AB ∥ line EF with transversal segment GJ 1. Given
2. angle AKG is congruent to angle BKL 2. Vertical Angles Theorem
3. angle BKL is congruent to angle ELK 3. Alternate Interior Angles Theorem
4. angle AKG is congruent to angle ELK 4. Transitive Property

Answers

The proof that is completed incorrectly is Michael's proof of the statement "corresponding angles AKG and ELK are congruent."

Both proofs start with the same given information – lines AB and EF are parallel, and transversal segment GJ crosses line AB at point K and crosses line EF at point L. Both proofs also rely on the same theorems – the vertical angles theorem and the alternate interior angles theorem. However, the difference is in the way the two proofs make the jump from the first three statements to the fourth statement.

In Michael's proof, statement number 3 is incorrect. Statement 3 in Michael's proof states that "angle BKL is congruent to angle ELK" based on the alternate interior angles theorem. However, this statement is not true because the interior angle BKL is not formed by the intersection of two straight lines from a point on the line AB and a point on the line EF, which is required for the alternate interior angles theorem to apply.

In contrast, Derrick's proof uses the vertical angles theorem before applying the transitive property in statement 4. The statement "angle AKG is congruent to angle ELK" in Derrick's proof is a result of applying the transitive property to the statement that "angle AKG is congruent to angle BKL" in statement 3 and the statement that "angle BKL is congruent to angle ELK" in statement 2, which are both results of applying the vertical angles theorem. This is a valid proof.

Therefore, Michael's proof is incorrect because of an incorrect application of the alternate interior angles theorem, while Derrick's proof is correct because it uses the vertical angles theorem and applies the transitive property correctly.

In hoping to make it onto the school's Gold Team, Bryan, Eli,and Damien took golf lessons over the summer.Bryan signed up to take 4 lessons with a semi-pro instructor, and each lesson cost $32.00 for a 45-minute session. The instructor advised Bryan to buy a bag of bulk practice balls to use during his lessons. After buying a bag of 32 golf balls, the total cost for his lessons and golf balls is $132.48.
Eli signed up to take 6 lessons with a pro instructor, and each lesson cost $52.00 for a 1-hour session. Eli bought a bag of bulk practice balls to use during his lessons. After buying a bag of 40 golf balls, the total cost for his lessons and golf balls is $319.20.
Damien signed up to take 5 lessons with pro instructor, and each lesson cost $28.00 for a 30-minute session. Based on the instructor's advise, he bought a bag of 24 golf balls to use during his lessons. The total cost for his lessons and golf balls is $144.08.
Place the students in order from the least amount to the greatest amount that they paid per golf ball.

Answers

bryan: 32*4 = 128

132.48 - 128 = 4.48

4.48 /32 = 0.14 per golf ball

Eli: 52 *6 = 312

319.20 - 312 = 7.20

7.20 / 40 = 0.18 per golf ball

Damien: 28*5 = 140

144.08 - 140 = 4.08

4.08 / 24 = 0.17 per ball


 least to greatest:

Bryan, Damien, Eli
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