What is the maximum mass of methane (CH4) that can be burned if only 1.0 g of oxygen is available and how do you figure it out?
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For 2*32=64 grams of oxygen, you can burn 2*16=32 grams of methane (that is, half).
So, our answer is .5g.
Other intermediate calculations are mollecular masses:
Answer:
0.28 g of
Explanation:
You need a balanced equation first. ⇒
You need to find the number of moles of oxygen, which is mass divided by the Mr: 1 ÷ 32 = 1/32
Then you find the moles of methane using the mole ration oxygen to methane 2:1. 1/32 ÷ 2 = 1/64
Then you find the mass by multiplying the Mr with the number of moles:
1/64 × 18 = 0.28125 g = 0.28 g
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Answers
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Answer:
6.43 moles of NF₃.
Explanation:
The balanced equation for the reaction is given below:
N₂ + 3F₂ —> 2NF₃
From the balanced equation above,
3 moles of F₂ reacted to produce 2 moles of NF₃.
Finally, we shall determine the number of mole of nitrogen trifluoride (NF₃) produced by the reaction of 9.65 moles of Fluorine gas (F₂). This can be obtained as follow:
From the balanced equation above,
3 moles of F₂ reacted to produce 2 moles of NF₃.
Therefore, 9.65 moles of F₂ will react to to produce = (9.65 × 2)/3 = 6.43 moles of NF₃.
Thus, 6.43 moles of NF₃ were obtained from the reaction.
b. the ozone layer
c. banded iron formations
d. stromatolites
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Answer;
Banded iron formations
Before free oxygen gas became abundant in the oceans and atmosphere, it reacted with a metal and produced banded iron formations.
Explanation;
- Cyanobacteria are thought to have introduced oxygen into the early atmosphere. This was important because oxygen played a key role in the evolution of eukaryotic organisms creating an ozone layer to shield life from UV rays.
- Banded iron layers were formed in sea water as the result of oxygen released by the photosynthetic cyanobacteria. As the photosynthetic organisms released oxygen, the available iron in the Earth's oceans precipitated out as iron oxides.
Answers
(1) CH3CH2CH2CH2CH2OH = n-pentanol (pentane-1-ol)
(2) CH3CH2CH2CH(OH)CH3 = 2-pentanol (pentane-2-ol)
(3) CH3CH2CH(OH)CH2CH3 = 3-pentanol (pentane-3-ol)
(4) CH3CH2CH(CH3)CH2OH = 2-methyl-1-butanol
(5) CH3CH2C(CH3)(OH)CH3 = 2-methyl-2-butanol
(6) CH3CH(OH)CH(CH3)CH3 = 3-methyl-2-butanol
(7) CH2(OH)CH2CH(CH3)CH3 = 4-methyl-1-butanol
(8) CH3CH(CH3)CH2CH2OH = 3-methyl-1-butanol
(9) CH3C(CH3)2CH2OH = 2,2-dimethyl-1-propanol
Ether isomers:
(1) CH3CH2CH2CH2-O-CH3 = methyl butyl ether
(2) CH3CH2CH2-O-CH2CH3 = ethyl propyl ether
(3) CH3CH(CH3)CH2-O-CH3 = methyl isobutyl ether
(4) CH3CH2CH(CH3)-O-CH3 = methyl sec-butyl ether
(5) CH3CH2-O-CH(CH3)CH3 = methyl isopropyl ether