Which of the following terms are like terms?a) 9x and 9y b)12ac^2 and ac^2 c)8xy and 8xz d)ab^2 and x^2y
Answers
A) 9x and 9y <-- those are different variables. This is incorrect.
B) 12ac^2 and ac^2 <-- those are the same variables and same exponent. Correct.
C) 8xy and 8xz <-- different variables, incorrect.
D) ab^2 and x^2y <-- different variables, incorrect.
Correct answer is
Out of all your choices, answer choice B) 12ac^2 and ac^2 fits that definition.
B is your answer.
Related Questions
Find the rate of change and the initial value for both group n individual session
Gary has 2 apple pies and each is divided into 8 equal parts. He serves of the first pie. How much pie does he have left?
kurt drives a total of 32 miles to and from work everyday. he works 5 days a week. how many miles does kurt drive in a week for his job?
For every penny Sam puts into his bank, Tara puts 4 pennies into her bank. If Sam puts 10 pennies into his bank, how many pennies does Tara put into her bank? Answer options with 4 options
Answers
Answer:
Down payment is $43,000
Step-by-step explanation:
If purchase price of anything = $215,000
Down payment = 20% of the price
20% of 215,000
= × 215,000
= 0.20 × 215,000
= $43,000
20% down payment on a purchase price of $215,000 is $43,000.
0.20(215,000) = 43,000
Answers
y^4 x y^6 = y^10
2) first card is a jack of diamonds or a queen 3) at least one card is a picture card
4)not more than one card is a picture card
5) the cards and not of the same suit
6) the second card is not a heart
7) the second card is not a heart given that the first card is a heart
8) the cards are Aces or diamond or boats
Answers
1) 4/52 * 48/51 = 192/2652 = 16/221
( explanation : 4- the number of kings, 52- the number of all cards on the pack, 48 - the number of other cards, 51- the number of cards that remain after picking first card)
2) (1/52+4/52) * 51/51 = 5/52 * 1 = 5/52
( in brackets are probabilities that 1st card is jack diamond or a queen )
3) 12/52 * 11/51 + 12/52 * 40/51 + 40/52 * 12/51= 91/221
( first is the probability that there are no picture cards, then one picture card: probability 12/52 * 40/51 that 1st is picture card and 40/51 * 12/52 that 2nd is a picture card)
4) 40/52 *39/51 + 12/52 *40/51 + 40/52 * 12/51= 210/221
5) 13/52 * 39/51= 169/884
( first is one suit and 2nd is another)
6) 39/52 * 38/51 + 13/52 + 39/51= 19/34
7)13/52 * 39/51 = 13/68
8) 4/52 * 3/51 + 13/52 * 12/51 + 4/52 * 12/51 + 1/51 =29/663
Answers
Answers
Answer:
ABQ = 139
BCR is the same as QBC since they are alternate interior angles
BCR = 41
Step-by-step explanation:
CBQ and SCB are same side interior angles so they add to 180
2a-9 + 5a +14 = 180
Combine like terms
7a +5 = 180
Subtract 5 from each side
7a = 175
Divide by 7
7a/7 = 175/7
a = 25
ABQ is the same as SCB since they are corresponding angles so
ABQ = SCB = 5a+14 = 5*25+14 = 125+14 = 139
BCR is the same as QBC since they are alternate interior angles
BCR = QBC = 2a-9 = 2*25 -9 = 50-9 = 41
3x − 2 = 5(x + 2)
3x − 2 = 5x + 10
8x = 8
x = 1
Answers
The original equation: 7(x + 2) = 2x − 1
Eliminate parentheses on the left: 7x + 14 = 2x - 1
Subtract 2x from each side: 5x + 14 = -1
Subtract 14 from each side: 5x = -15
Divide each side by 5 : x = -3
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Jeff thought he had solved a similar equation, but his solution is not correct.
Here are his steps, with my commentary:
3x − 2 = 5(x + 2) The original equation, to be solved.
3x − 2 = 5x + 10 Eliminated parentheses on the right, correctly.
8x = 8 Subtracted 5x from each side, incorrectly.
Left side should be -2x, not 8x .
Added 2 to each side, incorrectly.
Right side should be 12, not 8.
x = 1 Divided each side by 8, correctly.
But the input from the previous step was garbage,
so the output from this one is garbage.
Jeff should have taken a moment to check his solution,
back in the original equation.
The original equation: 3x − 2 = 5(x + 2)
If x = 1, then 3(1) - 2 = 5 (1 + 2)
3 - 2 = 5 (3)
1 = 15 I'm afraid not.
Poor Jeff.