There are 8 volunteers at the telethon. The goal for the evening is to raise $952. If each volunteer raises the same amount, what is the minimum amount each needs to raise to meet the goal

Answers

Answer 1
Answer: You have to divide 8 by 952 .952 รท 8= 119. 119 is your answer
Answer 2
Answer: You have to divide the money by the volunteers. 952/8=119

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I need help for this questionwhat's the equation for the following:

write the equation of the line perpendicular to y=1/3x-4 and passes through the point (-2,1)

Answers

Standard form:
y - 1 =  - 3(x  + 2)
Slope-intercept:
y =  - 3x  - 5

I REALLY NEED HELP PLZ!!!! PICTURE DOWN BELOW!the graph represents the last five years of computer hard drive production for Quality hard disks.
Part A
the variable T represents the time (in years). List the ordered pairs for t = 1 and t= 2
Part B
write an equation to represent the relationship between the time, t, and the number of hard disk produced ,p.

Answers

Part A:
To do this you have to find where t=1 and where 1=2. Then you have to go up the y axis (the vertical axis) until you hit a dot. For example, t=1, from t=1 you go up until you reach the dot which is located a 1,200. Then the ordered pair is (x [number of hard disks produced] ,y [time]) so it would be (1,1200)
Part B:
To do this you have to find a pattern between the x and the y coordinates. Easiest way is to divide the y by the x and see fi that works for all of the points.  Example: (1,1200) 1200/1=1200 (2,2400) 2400/2=1200. Bingo! The relationship is multiple the x (t) coordinate by 1200. The equation would look like this: 1200t=p

What is the approximate circumference of a semicircle with a radius of 30 centimeters

Answers

Approximate circumference of a semicircle with a radius of 30 centimeters is 94.2 centimeter

Solution:

Given semicircle with a radius of 30 centimeters

To find: approximate circumference of a semicircle

To find circumference of semicircle we can divide the circumference of circle by 2

circumference of semicircle = circumference of circle / 2

\text{ circumference of semicircle} = (2 \pi r)/(2) = \pi r

Substituting the given radius = 30 cm,

\text{ circumference of semicircle} = 3.14 * 30 = 94.2

Thus approximate circumference of a semicircle with a radius of 30 centimeters is 94.2 centimeter

Answer:

94.2

Step-by-step explanation:

A school wishes to enclose its rectangular playground using 480 meters of fencing.Suppose that a side length (in meters) of the playground is , as shown below.


(a) Find a function that gives the area A(x) of the playground (in square meters) in terms of x.

(b) What side length x gives the maximum area that the playground can have?

(c) What is the maximum area that the playground can have?

Answers

Answer:

Part a) A(x)=(-x^2+240x)\ m^2

Part b) The side length x that give the maximum area is 120 meters

Part c) The maximum area is 14,400 square meters

Step-by-step explanation:

The picture of the question in the attached figure

Part a) Find a function that gives the area A(x) of the playground (in square meters) in terms of x

we know that

The perimeter of the rectangular playground is given by

P=2(L+W)

we have

P=480\ m\nL=x\ m

substitute

480=2(x+W)

solve for W

240=x+W\nW=(240-x)\ m

Find the area of the rectangular playground

The area is given by

A=LW

we have

L=x\ m\nW=(240-x)\ m

substitute

A=x(240-x)\nA=-x^2+240x

Convert to function notation

A(x)=(-x^2+240x)\ m^2

Part b) What side length x gives the maximum area that the playground can have?

we have

A(x)=-x^2+240x

This function represent a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

The x-coordinate of the vertex represent the length that give the maximum area that the playground can have

Convert the quadratic equation into vertex form

A(x)=-x^2+240x

Factor -1

A(x)=-(x^2-240x)

Complete the square

A(x)=-(x^2-240x+120^2)+120^2

A(x)=-(x^2-240x+14,400)+14,400

A(x)=-(x-120)^2+14,400

The vertex is the point (120,14,400)

therefore

The side length x that give the maximum area is 120 meters

Part c) What is the maximum area that the playground can have?

we know that

The y-coordinate of the vertex represent the maximum area

The vertex is the point (120,14,400) -----> see part b)

therefore

The maximum area is 14,400 square meters

Verify

x=120\ m

W=(240-120)=120\ m

The playground is a square

A=120^2=14,400\ m^2

Final answer:

The width of the playground is 120 meters, the side length that gives the maximum area is 120 meters, and the maximum area the playground can have is 14400 square meters.

Explanation:

(a) Let's assume the width of the rectangle is x meters. Since the playground is rectangular and has two equal sides, the length will also be x meters. The perimeter of the rectangle, which is also the amount of fencing needed, is given as 480 meters. This can be expressed as: 2(length + width) = 480. Using this equation, we can solve for the width: 2(x + x) = 480 โ‡’ 4x = 480 โ‡’ x = 480/4 = 120. Therefore, the width of the playground is 120 meters.

(b) To find the side length that gives the maximum area, we can use calculus. The area function is A(x) = x * x = x^2. To find the maximum of this function, we can take the derivative and set it equal to zero: dA/dx = 2x = 0 โ‡’ x = 0. So, x = 0 is a critical point, but since we are dealing with a physical situation where the length cannot be zero, we disregard this critical point. Thus, x = 120 is the value that gives the maximum area.

(c) Now that we know the side length, we can calculate the maximum area. Plugging in x = 120 into the area function, we find: A(120) = 120 * 120 = 14400 square meters. Therefore, the maximum area the playground can have is 14400 square meters.

Learn more about Area of a rectangle here:

brainly.com/question/15218510

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3 people share 7 cookies. How many cookies does each friend get?

Answers

2 and 1/3 because

2+2+2=6
1/3+1/3+1/3=3/3 or 1

6+1 is 7
The answer is 2 and 1/3

Working With Inequalities
Solve This Problem:
8 > 8n
Thank you all in advance!

Answers

the answer to your question is n<1