If the acetylene tank contains 37.0 mol of C2H2 and the oxygen tank contains 81.0 mol of O2, what is the limiting reactant for this reaction?

Answers

Answer 1
Answer:

Answer: O_2 is considered as the limiting reagent for this reaction.

Explanation:

Limiting reagent is the reagent which limits the formation of the product.

Excess reagent is the reagent which is present in excess in a chemical reaction.

For the combustion of acetylene, the reaction follows:

2C_2H_2(g)+5O_2(g)\rightarrow 4CO_2+2H_2O

By Stoichiometry,

5 moles of oxygen gas reacts with 2 moles of acetylene.

So, 81 moles of oxygen gas will react with = (2)/(5)* 81 = 32.4 moles of acetylene.

As, the required amount of acetylene is less than the given amount. So, it is considered as an excess reagent and oxygen gas is the limiting reagent.

Answer 2
Answer:

Answer:

Oxygen is the limiting reactant of this reaction.

Explanation:

2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O

2 moles of acetylene reacts with 5 moles of oxygen.

Then 37 moles of acetylene will react with :

(5)/(2)* 37.0 mol=92.5 moles of oxygen gas.

But only 81 moles of oxygen gas is present.

Then 81.0 moles of oxygen gas will react with:

(2)/(5)* 81.0 mol=32.4 moles of acetylene.

And still acetylene will remain after.

So, from the above calculation we cans see that oxygen is present in limiting amount which will limit the reaction.Hence, the limiting reactant of this reaction is oxygen.


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Answers

Answer:

O-16 isotope is most likely to have the greatest abundance in nature.

Explanation:

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  • O-18: 17.999 amu

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Answers

Answer:

Explanation:

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Answers

We know,
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The moles of Na+ present:
0.5 L * 0.001 mol/L
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Answers

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Answers

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P is the symbol
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d. Water can dissolve nonpolar covalent compounds through dipole-dipole interactions.

Answers

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Answer:

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Explanation:

It's the correct answer on Edge 2021. If anyone asks, you didn't hear it from me ;)