a box of 10 markers weighs 105 grams. if the empty box weights 15 grams, how much does each marker weigh?

Answers

Answer 1

Answer: first, ,how much do all the markers weight? the box with the markers weights 105, so without the box all the markers weigh 105-15=90 grams.

so 90 grams is the weight of 10 markers together, and each of them will weigh one tenth of this: 90/10=9

so each marker weights 9 grams.

Answer 2

Answer:

Final answer:

The weight of each marker can be found by first subtracting the weight of the empty box from the total weight to get the weight of all markers, then dividing by the number of markers. Each marker weighs 9 grams.

Explanation:

Firstly, we can find the total weight of the markers by subtracting the weight of the empty box from the total weight of the box with the markers. Doing this calculation (105 grams - 15 grams) gives us the total weight of the markers, which is 90 grams. As there are 10 markers, we can find the weight of each marker by dividing the total weight of the markers by the number of markers. This calculation (90 grams / 10) results in each marker weighing 9 grams.

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Answers

Answer:

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Step-by-step explanation:

Given

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Answers

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Answers

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What is the value of t in the equation t−35=-15?

Answers

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

t/15-t/35-(1/15)=0

Step by step solution :Step 1 : 1 Simplify —— 15 Advertising SkipEquation at the end of step 1 : t t 1 (—— - ——) - —— = 0 15 35 15 Step 2 : t Simplify —— 35 Equation at the end of step 2 : t t 1 (—— - ——) - —— = 0 15 35 15 Step 3 : t Simplify —— 15 Equation at the end of step 3 : t t 1 (—— - ——) - —— = 0 15 35 15 Step 4 :Calculating the Least Common Multiple :

4.1    Find the Least Common Multiple

      The left denominator is :       15

      The right denominator is :       35

        Number of times each prime factor
        appears in the factorization of: Prime
Factor  Left
Denominator  Right
Denominator  L.C.M = Max
{Left,Right} 310151117011 Product of all
Prime Factors 1535105

Least Common Multiple:
105

Calculating Multipliers :

4.2    Calculate multipliers for the two fractions

    Denote the Least Common Multiple by  L.C.M
    Denote the Left Multiplier by  Left_M
    Denote the Right Multiplier by  Right_M
    Denote the Left Deniminator by  L_Deno
    Denote the Right Multiplier by  R_Deno

   Left_M = L.C.M / L_Deno = 7

   Right_M = L.C.M / R_Deno = 3

Making Equivalent Fractions :

4.3 Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respectiveMultiplier.

L. Mult. • L. Num. t • 7 —————————————————— = ————— L.C.M 105 R. Mult. • R. Num. t • 3 —————————————————— = ————— L.C.M 105 Adding fractions that have a common denominator :

4.4 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

t • 7 - (t • 3) 4t ——————————————— = ——— 105 105 Equation at the end of step 4 : 4t 1 ——— - —— = 0 105 15 Step 5 :Calculating the Least Common Multiple :

5.1    Find the Least Common Multiple

      The left denominator is :       105

      The right denominator is :       15

        Number of times each prime factor
        appears in the factorization of: Prime
Factor  Left
Denominator  Right
Denominator  L.C.M = Max
{Left,Right} 311151117101 Product of all
Prime Factors 10515105

Least Common Multiple:
105

Calculating Multipliers :

5.2    Calculate multipliers for the two fractions

    Denote the Least Common Multiple by  L.C.M
    Denote the Left Multiplier by  Left_M
    Denote the Right Multiplier by  Right_M
    Denote the Left Deniminator by  L_Deno
    Denote the Right Multiplier by  R_Deno

   Left_M = L.C.M / L_Deno = 1

   Right_M = L.C.M / R_Deno = 7

Making Equivalent Fractions :

5.3 Rewrite the two fractions into equivalent fractions

L. Mult. • L. Num. 4t —————————————————— = ——— L.C.M 105 R. Mult. • R. Num. 7 —————————————————— = ——— L.C.M 105 Adding fractions that have a common denominator :

5.4 Adding up the two equivalent fractions

4t - (7) 4t - 7 ———————— = —————— 105 105 Equation at the end of step 5 : 4t - 7 —————— = 0 105 Step 6 :When a fraction equals zero : 6.1 When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

4t-7 ———— • 105 = 0 • 105 105

Now, on the left hand side, the 105 cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :
4t-7 = 0

Solving a Single Variable Equation :

6.2      Solve  :    4t-7 = 0

Add  7 to both sides of the equation :
                      4t = 7
Divide both sides of the equation by 4:
                     t = 7/4 = 1.750

Factor the. expression x^2+ 18x +80