Suppose Y varies directly as X, and y = 9 when x = 3/2. Find y when x = 1.

Answers

Answer 1
Answer:

Answer:  The required value of y is 6.

Step-by-step explanation: We are given that y varies directly as x and y = 9 when x=(3)/(2).

We are to find the value of y when x = 1.

According to the given information, we have

y\propto x\n\n\Rightarrow y=k* x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{where k is the constant of integration}]\n\n\Rightarrow y=kx~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

When y = 9 and x=(3)/(2), we have from equation (i) that

9=k*(3)/(2)\n\n\n\Rightarrow k=(18)/(3)\n\n\Rightarrow k=6.

So, equation (i) becomes

y=6x.

Therefore, when x = 1, we get

y=6*1=6.

Thus, the required value of y is 6.

Answer 2
Answer: to vary directly is to be in proportion

y/x = y/x

9/(3/2) = y
9(2/3) = y
y = 6

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