Answer:
The center of the circle is point: C=(1,5).
The radius of the circle is r=3.
Step-by-step explanation:
x² + y² -2x - 10y + 17 = 0
Find the center and radius of this circle
We have the equation
x² + y² -2x - 10y + 17 = 0
We collect like terms
x² - 2x + y² - 10y = -17
x² - 2x + (-2/2)² + y² - 10y + (-10/2)² = -17 + (-2/2)² + (-10/2)²
The center of the circle is point: C=(1,5).
The radius of the circle is r=3.
42 cups of sugar should be used if 21 cups of flour are used
A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0.
Given,
For a given recipe, 12 cups of flour are mixed with 24 cups of sugar
We need to find cups of sugar should be used if 21 cups of flour are used
Let us consider x as cups of sugar should be used if 21 cups of flour are used
Let us form an equation to find x
12/24=21/x
Apply cross multiplication
12x=21×24
12x=504
Divide both sides by 12
x=504/12
x=42
Hence, 42 cups of sugar should be used if 21 cups of flour are used
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Answer:
33 cups of sugar should be used
Step-by-step explanation:
subtract 12 from 21 then add that answer to 24 and you get 33 so 33 cups of sugar should be used
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Answer:
-5x(x + 2)
Step-by-step explanation:
the key is factoring:
-5x² - 10x = -5x × (x) - 5x × (2) {here we notice that -5x is a common factor}
= -5x(x + 2)
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Answer:
hope this helps you
Answer:Use A for third graders, B for fourth graders, and C for fifth graders.
33 = A + B + C
Since there are three variables, you need to come up with two other equations to substitute in.
C = 6 + A Since there are six more fifth graders than third graders.
A = B Since there is an equal amount of third and fourth graders.
Since A is in both equations, lets put each variable in terms of A.
B = A
C = 6 + A
So: A+A+A+6=33
A+A+A=27 Since you subtract six from both sides.
3A=27 Since you combine all three A's.
A=9 Since you divide both sides by three.
Therefore, since A is the number of third graders, there are 9 third graders.
Step-by-step explanation:
Answer:
Step-by-step explanation:
We have been given a function:
We will compare it with the genral equation which is:
Where, a is amplitude and period of function is
In given equation a is -3 and b is 4
So, period of the given equation is:
Yo can look at the graph in the attachment.
The a is the amplitude and the period of the function is
We have been given a function
We will compare it with the general equation which is
Where a is amplitude and period of the function is
In the given equation a is -3 and b is 4
So, the period of the given equation is:
You can look at the graph.
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