The cost of a gallon of orange juice is 3.50. What is the maximum number of can trainers you can buy for $15?

Answers

Answer 1

Answer:

We have that for the Question "The cost of a gallon of orange juice is 3.50. What is the maximum number of can trainers you can buy for $15?" it can be said that the maximum number of can trainers you can buy for $15 is

x=4.285

From the question we are told

The cost of a gallon of orange juice is 3.50. What is the maximum number of can trainers you can buy for $15?

Generally the equation for the maximum number is mathematically given as

$x=(amount you have)/(price)\n\nx=(15)/(3.50)$

x=4.285

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Answer 2

Answer: WORK:
$15 ÷ $3.50 = 4.285714386
4.285714386 ≈ 4
ANSWER:
The maximum number of containers you can buy for $15 is 4 containers.

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Larry needed to by 5 books at the same price. After he uses a $30 gift card, he can spend no more than $50. What is the maximum cost of each book that he can buy?

Answers

Answer:

The maximum cost of each book will be $14 that Larry can buy.

Step-by-step explanation:

Given:

Gift card = $30

Maximum amount can be spend = $50

number of books need to buy = 5

We need to find maximum cost of each book.

Solution:

Let the cost of each book be 'x'.

So we can say that;

Sum of money of gift card and maximum money he can spend should be greater than or equal to number of books need to buy multiplied by cost of each book.

framing in equation form we get;

$5x\leq 30+50\n\n5x\leq 80$

Dividing both side by 5 we get;

$(5x)/(5)\leq (80)/(5)\n\nx\leq\$14$

Hence The maximum cost of each book will be $14 that Larry can buy.

Solve: (6x^3 - 1x^2 + 1) divided by (2x + 1)a. -3x^2 + 2x -1
b. 3x^2 - 2x + 1
c. -3x^2 + 2x - 1
d. 3x^2 2x - 1

Answers

The Simplified answer would be b. 3x^2 - 2x + 1

Find the value of x. Round to nearest hundredth if necessary.

Answers

The side on the front of 30° is 1/2 of hypytenuse
Then 1/2 of 4=2 and the ather side with theorem of pytagore is squares root of(4^2-2^2)=sq .root of 12
This side(square root of 12) is 1/2 of hypotenuse then
Hypotenuse is 2*square root 12
X^2=(2*sq .root12)^2 -(square root 12)^2
X^2=48-12=36
X=6

Suppose we toss a coin 4 times. how many different sequences of outcomes are possible if order matters? (for example, hhtt is one outcome and htht is counted as a different outcome)