The potential energy of a 40 kg cannon ball is 14000 J. How high was the cannon ball to have this much potential energy?

Answers

Answer 1
Answer:

From the information given, cannon ball weighs 40 kg and has a potential energy of 14000 J.

 We need to find its height.

We will use the formula P.E = mgh

Therefore h = P.E / mg

where P.E is the potential energy,

 m is mass in kg,  

g is acceleration due to gravity (9.8 m/s²)

 h is the height of the object's displacement in meters.

h = P.E. / mg

h = 14000 / 40 × 9.8

h = 14000 / 392

h = 35.7

Therefore the canon ball was 35.7 meters  high.



Answer 2
Answer:

Final answer:

The height of the cannon ball to have 14000 J of potential energy is approximately 357.14 meters. This is calculated using the formula for potential energy: PE = mgh, and solving for 'h'.

Explanation:

The potential energy (PE) of an object is given by the formula PE = mgh, where 'm' is the mass of the object, 'g' is the acceleration due to gravity (standard approximate value is 9.8 m/s² on Earth), and 'h' is the height. In your question, we want to find the height 'h'. Given that the potential energy is 14000 J and the mass of the cannon ball is 40 kg, we can rearrange the formula to solve for 'h': h = PE / (m*g).

So, inputting the given values, h = 14000 J / (40 kg * 9.8 m/s²). Solving this, we find that the height is approximately 357.14 meters. This means the cannon ball was at around this height to have 14000 J of potential energy.

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Answers

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- Increasing the distance by a factor of √(2)

Explanation:

There are no options provided, however we can still answer the question.

In fact, the magnitude of the gravitational force between two objects is given by  the equation:

F=G(m_1 m_2)/(r^2)

where

G=6.67\cdot 10^(-11) m^3 kg^(-1)s^(-2) is the gravitational constant

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r is the separation between them

We notice that:

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Therefore, in order to reduce the gravitational attraction by one half, we can do one of the following changes:

- Decreasing one of the masses to 1/2 of its original value: for example, if m_1'=(1)/(2)m_1, the gravitational force becomes

F'=G(m_1' m_2)/(r^2)=G((1)/(2)m_1m_2)/(r^2)=(1)/(2)(G(m_1m_2)/(r^2))=(1)/(2)F

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F'=G(m_1 m_2)/(r'^2)=G(m_1m_2)/((√(2)r)^2)=(1)/(2)(G(m_1m_2)/(r^2))=(1)/(2)F

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 Optional Answers:

 

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  B. The warm and cold air both disappear.

  

  C. The warm and cold air mix immediately.

 

  D. The cold air rises. 

Answers

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This is an essay don't make it to long but please help its scienceSome constellations, such as ursa minor, are visible in the sky year round: other constellations appear for only part of the year. Explain why this happens?

A few sentences will do *3-4 sentences is perfect*

Answers

Answer:

This is because of the different latitudes and the movement of the stars.

Explanation:

Some constellations can be seen throughout the year and others only at certain times. In addition to the appearance of the night sky changing throughout the year, it also depends on latitude, that is, the appearance of the sky at the same time is different at different latitudes. For example, you can see the Polar star in the northern hemisphere but you cannot see it in the southern hemisphere. Cruzeiro do Sul, seen in the southern hemisphere, is only seen in the northern hemisphere, close to the horizon, in the tropical region.

Another important difference between the two hemispheres is in the movement we observe for the stars over the course of a night as they revolve around the north celestial pole (in the northern hemisphere) clockwise and around the south celestial pole (in the southern hemisphere) in anticlockwise.

In astronomy circumpolar constellations are those ones which never set from viewer's perspective like ursa minor, cassiopiea etc.

Because of the rotation of the Earth and its orbit around the Sun, we divide the stars and constellations into two groups. Some stars and constellations never rise nor set, and they are called circumpolar. All the rest are divided into seasonal stars and constellations. Which stars and constellations will be circumpolar and which seasonal depends on your latitude. 

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Answers

Answer:

I only really know the "How do we use these EM waves in our lives?" part srry

Explanation:

EM waves are used to make sure you cellphone, radio, TV, and etc. have service/ connection.

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We use these everyday in our life however they also have dangers.

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Microwaves - used for heating up food and transferring heat to the food.
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Infrared - can be used for remote controls and security cameras.
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Answers

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Which action will result in a product with new chemical properties?A. shredding a newspaper

B. breaking a mirror

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D. popping popcorn

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Answers

Popping popcorn action will result in a product with new chemical properties, therefore the correct answer for the given problem is option D.

What is a chemical reaction?

In a chemical reaction, one or more components referred to as reactants—are changed into one or more other substances—also referred to as byproducts.

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The energy of the reactant is greater than the energy of the product because the extra energy is released during an exothermic reaction.

Popcorn would be the best choice since it would transform the pre-popped kernels into something else whereas the other options would merely change their outward look.

Thus, popping popcorn action will result in a product with new chemical properties, therefore the correct answer for the given problem is option D

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the answer would be popping popcorn because while you are changing the physical appearance in the rest of the choices only popping the popcorn would turn the prepopped kernels into something else