What is the simplified form of the quantity of x plus 4, all over 5 + the quantity of x plus 5, all over 5
Answers
Same denominator, so put both numerators together on top of 5:
[(x+4) + (x+5)]/5
Combine like terms:
(2x+9)/5
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Answers
where (h,k) the point of the center of the circle
and (r) is the radius of the circle
so if the center of the circle = (-2,-4)
by subs. in the formula we get (x-(-2))^2 + (y-(-4))^2 = r^2
then the equation will be (x+2)^2 + (y+4)^2 = r^2
now we want to define the radius of the circle r
since point (3,8) lay on the circle so we can
then subs. in the equation to get the radius
(x+2)^2 +(y+4)^2 = r^2
(3+2)^2 +(8+4)^2 = r^2
25 + 144 = r^2
r^2 = 169
r= 13
the radius of the circle is 13
so by subs in the equation we get
(x+2)^2 + (y+4)^2 = 169
so it is the first answer in the choices
Answers
35×20%= 7. Alice has seven cars
(-4)2 =
Answers
(-4)(-4)
=16
(Positive sixteen)
Answer:
16
Step-by-step explanation:
medals?
Decide if the situation involves a permutation or a combination, and then find
the number of ways to award the medals.
Answers
Answer: Permutation; number of ways = 120
Step-by-step explanation:
Answer with explanation:
Number of runner= 5
Number of Distinct Medal = 5
First Medal can be Awarded in 5 ways, second Medal can be awarded in 4 ways and third Medal can be awarded in 3 ways , fourth medal can be awarded in 2 ways and fifth Medal can be awarded in one way.
So, total number of ways =5 × 4×3×2×1=120 way
⇒We will use the concept of Permutation as there are five distinct medal and five different runners
So, Five distinct places can be filled in 5! or ways as order of arrangement is Important because any of the five candidates can win first second, third , fourth or fifth Prize.
= 5!=5×4×3×2×1=120 ways
Because, n!=n×(n-1)×(n-2)×........1.
Answers
Answer:
THERE YA GO BUDDY!!
Step-by-step explanation:
To work out the probability that both randomly chosen students have only visited Mexico, we need to consider the number of students who have visited Mexico and subtract those who have also visited other countries.
From the given information:
- 11 students have visited Canada
- 2 students have visited Canada and Mexico (but not the USA)
- 3 students have visited Mexico and the USA
- 1 student has visited all three countries
- 6 out of the 19 students who have visited the USA have also visited at least one of the other countries.
We can calculate the number of students who have only visited Mexico as follows:
Total students who have visited Mexico = Total students who have visited Mexico and the USA - Students who have visited all three countries - Students who have visited Canada and Mexico (but not the USA)
= 3 - 1 - 2
= 0
Since there are no students who have only visited Mexico, the probability that both randomly chosen students have only visited Mexico is 0.
Answers
minus 6 and 3=3
minus 17 and 20
3g=g
1=g
-3g=-3. Finally, divide both sides by -3. -3/-3 is 1, so G is 1.