Complete the following Empirical Formula & Molecular Formula problem:1.) A compound containing 63.15% C, 5.30% H, and 31.55% O. (Assume 100 g sample)

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Answer 1

Answer: 63.15% C ; 5.30% H; 31.55% O

1) Assume 100 g sample
63.15% C * 100 g = 63.15g
5.30% H * 100 g = 5.30g
31.55% O * 100g = 31.55g

2) Convert mass to moles using their atomic weights

63.15 g * 1 mol C / 12.0107 g C = 5.2870 mol C
5.30 g * 1mol H / 1.0079 g H = 5.2585 mol H
31.55 g * 1mol O / 15.9994 O = 1.9719 mol O

3) Divide each quantity by the smallest number of moles

5.2870 mol C / 1.9719 mol = 2.6812 C = 2 C
5.2584 mol H / 1.9719 mol = 2.6667 H = 2 H
1.9719 mol O / 1.9719 mol = 1.000 O = 1 O

Empirical Formula is C₂H₂O

If the problem is silent, the molecular weight is equivalent to the empirical weight.
To get the molecular formula, divide the molecular weight by the empirical weight to get the multiple.

Molecular Weight is not mentioned thus it is equivalent to Empirical Weight which is:

Atom Number in Molecule Atomic Weight Total Mass
C 2 12.0107 24.0214
H 2 1.0079 2.0158
O 1 15.9994 15.9994
Total weight is 42.0366

Molecular weight / Empirical Weight = Multiple to be multiplied to the Empirical Formula
42.0366 / 42.0366 = 1

Molecular Formula isC₂H₂O

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What information is necessary to determine the atomic mass of the element chlorine?(1) the atomic mass of each artificially produced isotope of chlorine, only
(2) the relative abundance of each naturally occurring isotope of chlorine, only
(3) the atomic mass and the relative abundance of each naturally occurring isotope of chlorine
(4) the atomic mass and the relative abundance of each naturally occurring and artificially produced isotope of chlorine

Answers

Answer is: (3) the atomic mass and the relative abundance of each naturally occurring isotope of chlorine.

m(³⁵Cl) = 34.97 amu; the average atomic mass of chlorine-35.

m(³⁷Cl) = 36.97 amu; the average atomic massof chlorine-37.

ω(³⁵Cl) = 75.76% ÷ 100% = 0.7576; fractional abudance of chlorine-35.

ω(³⁷Cl) = 24.24% ÷ 100% = 0.2424; fractional abudance of chlorine-37.

m(Cl) = m(³⁵Cl) · ω(³⁵Cl) + m(³⁷Cl) · ω(³⁷Cl).

m(Cl) = 34.97 amu · 0.7576 + 36.97 amu · 0.2424.

m(Cl) = 35.4548 amu; average atomic mass of chlorine.

Final answer:

The atomic mass of chlorine is determined by both the atomic mass and the relative abundance of each naturally occurring isotope of chlorine. It's based on an average of the masses of the isotopes according to their relative abundance.

Explanation:

To determine the atomic mass of the element chlorine, option (3), both the atomic mass and the relative abundance of each naturally occurring isotope of chlorine is required. The atomic mass of chlorine is not just the mass of one particular atom, or isotope; instead, it's an average of the masses for all the isotopes according to their relative abundance. For instance, Chlorine has two isotopes Chlorine-35 and Chlorine-37. If the relative abundance of Chlorine-35 is 75% and that of Chlorine-37 is 25%, the atomic mass is calculated by the formula [(0.75 x 35) + (0.25 x 37)].

Learn more about Atomic Mass here:

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There are gps satellities orbiting the earth a) 28
b) 24
c) 42
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The GPS or global positioning system is a satellite – based navigation system made up of a network of 24 satellites placed into orbit by the US Department of Defense. It was originally intended for military applications but later one, it made available for civilian use. It works in any weather conditions, anywhere in the world for 24 hours a day.

I will give brailiest to whoever needs it!

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Which best describes nuclear fission

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Nuclear fission is either a nuclear reaction or radio active decay process in which nucleus (the center) of an atom splits into smaller parts called nuclei. This is an extremely exothermic reaction (i.e a reaction which produces heat) resulting into release of massive amount of energy in the form of heat and sometimes light. The reaction produces much more energy as compared to a similar mass of a conventional fuel, such as Petrol/Kerosene/Petroleum Gas etc. This makes Nuclear fission an extremely dense and at times very destructive source of energy. Some common elements capable of Nuclear fission are Uranium, Plutonium etc. Though in modern days Nuclear Fission are finding application in being a source of energy (such as a Nuclear power plant), but they are also used in destructive format as Nuclear Bombs and it's one of the top most imminent threats to the existence of humanity in future (in the event of a Nuclear war).

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Determining nitrogen balance in the clinical setting can be very valuable. To determine a client’s state of nitrogen balance, a 24-hour urinary urea nitrogen collection is done. What do you also need to do?

Answers

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We also need the nitrogen intake

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What is the oxidation number of chlorine in HClO4?

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