Your dog is 16 years old in dog years. Your cat is 28 years old in cat years. For every human year, your dog ages by 7 dog years and your cat ages by 4 cat years. In how many human years will both pets be the same age in their respective types of years?
Answers
This question is based on the concept of graphical method. Therefore, In 4 years, human years will both pets be the same age in their respective types of years.
Given:
Your dog is 16 years old in dog years.
Your cat is 28 years old in cat years.
For every human year, your dog ages by 7 dog years and your cat ages by 4 cat years.
Let x be the no. of human yrs.
We have to find x such that age is same for dog and cat in their respective year i.e.
16 + 7x = 28 + 4x
Write above equation as follows and solve it graphically,
y = 16 + 7x
y = 28 + 4x
From the graph, it is observe that. Attachment is below.
Point of intersection is (4, 44). Thus, solution of equation is x =4.
Now put the value x = 4 in equation 16 + 7x = 28 + 4x.
We get,
16 + 7(4) = 28 + 4(4)
44 = 44
Therefore, In 4 years, human years will both pets be the same age in their respective types of years.
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(a): The original perimeter is 2(x+y), but the new one is 2(2x+2y). This is twice the original perimeter, so it is 18*2=36.
(b): The original area is xy, and the new one is (2x)(2y), or 4xy. This is four times the original area, or 20*4=80.
(c): As it's given that the side lengths are integers, the intended solution is most likely to divide by 2 in the perimeter to see that the sum of the side-lengths is 9 and their product is 20. Guessing/checking values for each side, we see that 4 and 5 work for the smaller rectangle. Multiplying by two, the larger one has lengths 8 and 10.
Alternatively, we set them to x and y and use the equations:
x+y=9
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