MATHEMATICS MIDDLE SCHOOL

Cheese sticks that were previously priced at "5 for $1" are now "4 for $1". Find the percent increase in the price per cheese stick.

Answers

Answer 1

Answer:

Answer

Find out the percent increase in the price per cheese stick.

To prove

As given

Cheese sticks that were previously priced at "5 for $1" are now "4 for $1".

i.e previously the price of the 5 cheese stick is $1 .

$one\ cheese\ sticks\ price = (1)/(5)$

= 0.2

Now the price of the 4 cheese stick is $1 .

$one\ cheese\ sticks\ price = (1)/(4)$

= 0.25

Change in price per cheese stick = now price - previous price

= 0.05

Formula

$Percentage\ increase = (Change\ in\ price\ per\ cheese\ stick* 100)/(Previous\ price\ per\ cheese\ stick)$

Put all the value in the formula

$Percentage\ increase = (0.05* 100)/(0.2)$

= 25%

Therefore the percent increase in the price per cheese stick is 25%.

Answer 2

Answer: the price of cheese sticks went from 5 for $1 ( $0.20) to 4 for $1 ($0.25)
.25-.20= .05
.05/.20= 25% increase in price per cheese stick

Related Questions

A rectangle has length 3 feet and width 1/4 foot. What is the area of the rectangle?
Three vertices of a square are (–2, 2), (–2, –3), and (3, –3). What is the fourth vertex of the square?A.(–3, 2)B.(–2, 3)C.(3, 2)D.(3, 4)
Find two square roots of 121/49
Is 45/5 equal to a whole number or a mixed number?Please Explain How You know
Write a description of how a diagram can help you solve 2 x 40.

Please help with number 2

Answers

Have you tried Dividing 80 by 15 since that's how he got 10% of 80

As a salesperson, you are paid $92 per week plus $4 per sale. This week you want your pay to be at least $200. Write an inequality for the number of sales you need to make, and describe the solutions.

Answers

The inequality function should be 4x + 92 ≥ 200.

Given that,

As a salesperson, you are paid $92 per week plus $4 per sale.
This week you want your pay to be at least $200.

Based on the above information, the equation is as follows:

4x + 92 ≥ 200.

Learn more:brainly.com/question/5101300?referrer=searchResults

4x + 92 ≥ 200

the $92 are regardless and you make $4 every sale (x) to solve this you would multiply the number of sales (x) by 4 then add the initial 92

Find the solution set of this inequality|10x+20| ≤10

Answers

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10* -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10* -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10* 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

the total cost of 3 tables & 2 chairs is rs 1850 ...if a table RS 75 more than a chair ,find the price of each ?

Answers

• We have the enunciation, now we can solve.
♦ We note :
- t, the price of the table;
-c, the price of a chair:

3t+2c=1850 }
t=c+75 } =>

=> 3(c+75) +2c=1850
3c+225+2c=1850
5c=1850-225
5c=1625
c=1625:5
c=341=> t=341+75 = 476 .

How is the product of 4 and 2 shown using integer tiles?A. ++++ ++
B. ---- --
C. ++ ++ ++ ++
D. -- -- -- --

Answers

Answer:

C. ++ ++ ++ ++

Step-by-step explanation:

Note that the numbers are positive 4 & positive 2 (which explains the + signs).

The answer can be two ways. 4 groups of 2, or 2 groups of 4.

C. ++ ++ ++ ++ is your answer, for it is 4 groups of 2. Note that A is not the answer, for that would be for adding, in which you have one group of 4 and one group of 2.

Answer:

Step-by-step explanation:

im smart

Write the inequality;
Eight less than a number is greater than 0 and less than or equal to 1.

Answers

1>N-8>0 the sign in between the 1 and the n should have a line under it

Other Questions

Which shows the GCF of 18 and 24 with 18/24 in the simplest form

Which system of equations can be used to solve the following problem? Each child ticket for a ride costs $2, while each adult ticket costs $6. If the ride collected a total of $148, and 38 tickets were sold, how many of each type of ticket were sold? Let c be the number of child tickets and a be the number of adult tickets. A. Equation set including begin equation begin product of two and c end product plus begin product of six and a end product equals thirty-eight end equation. Begin equation a plus c equals one hundred and forty-eight end equation. B. Equation set including begin equation begin product of two and a end product plus begin product of six and c end product equals thirty eight end equation. Begin equation a plus c equals one hundred and forty-eight end equation. C. Equation set including begin equation begin product of six and c end product plus begin product of two and a end product equals one hundred and forty-eight end equation. Begin equation c plus a equals thirty-eight end equation. D. Equation set including begin equation begin product of two and c end product plus begin product of six and a end product equals one hundred and forty-eight end equation. Begin equation a plus c equals thirty-eight end equation.

How would you solve 5,037 divided by 3

Explain what is the same about two fractions that are like fractions