MATHEMATICS MIDDLE SCHOOL

$1,200, 3.9%, 8months

Answers

Answer 1

Answer:

Answer:

$1231

Step-by-step explanation:

Given,

Principal amount = $1200

Rate of interest = 3.9%

Time = 8 months or (8/12) 0.666667 years

Formula of simple interest = $A=P(1+rt)$

$A=1200(1+(3.9* 0.666667)/(100))$

A = 1200(1+(0.039 × 0.666667))

A = 1200 (1+0.026)

A = 1200 (1.026)

A = $1231

Answer 2

Answer: 1,200(1.039)^.66666
1200(1.02583386437)
$1231.00

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Match the pairs of polynomials to their products. (xy + 9y + 2) and (xy – 3) x2y2 + 3x2y – 7xy – 27x – 18 (2xy + x + y) and (3xy2 – y) 6x2y3 – 2xy2 + 3x2y2 – xy + 3xy3 – y2 (x – y) and (x + 3y) x3y + 3x2 + 3x2y2 + 7xy – 6 (xy + 3x + 2) and (xy – 9) x2 – 9y2 (x2 + 3xy – 2) and (xy + 3) (x + 3y) and (x – 3y)

Answers

Answer:

Step-by-step explanation:

1) (xy+ 9y + 2) and (xy – 3)

Each term of second expression will be multiplied by first bracket.

xy(xy+9y+2) -3(xy+9y+2)

x²y²+9xy²+2xy-3xy-27y-6

x²y²+9xy²-xy-27y-6

2)(2xy + x + y) and (3xy2 – y)

3xy²(2xy+x+y) -y(2xy+x+y)

6x²y³+3x²y²+3xy³-2xy²-xy-y²

6x²y³ – 2xy² + 3x²y² – xy + 3xy³ – y²

3) (x – y) and (x + 3y)

x(x-y) +3y(x-y)

x²-xy+3xy-3y²

x²+2xy-3y²

4) (xy + 3x + 2) and (xy – 9)

xy(xy + 3x + 2) -9(xy + 3x + 2)

x²y²+3x²y+2xy-9xy-27x-18

x²y²+3x²y-7xy-27x-18

5) (x2 + 3xy – 2) and (xy + 3)

xy(x2 + 3xy – 2) +3(x2 + 3xy – 2)

x³y+3x²y²-2xy+3x²+9xy-6

x³y+3x²+3x²y²+7xy-6

6) (x + 3y) and (x – 3y)

x(x + 3y) -3y(x + 3y)

x²+3xy-3xy-9y²

x²-9y² ....

Answer: (xy + 9y + 2) and (xy – 3) —> x3y + 3x2 + 3x2y2 + 7xy – 6

(2xy + x + y) and (3xy2 – y) —> 6x2y3 – 2xy2 + 3x2y2 – xy + 3xy3 – y2

(x – y) and (x + 3y) —> (x + 3y) and (x – 3y)

(xy + 3x + 2) and (xy – 9) —> x2y2 + 3x2y – 7xy – 27x – 18

Step-by-step explanation:

I think that’s right I’m sorry if it’s not.

the ratio of the number of apples to the number of oranges is 4:6. The ratio of the number of oranges to the number of pears is 8:1. How many apples, Oranges and pears are there if there are 172 fruits.

Answers

The answer is 64 apples, 96 oranges, and 12 pears.

Let's represent the fruit as following:
a - the number of apples,
o - the number of oranges,
p - the number of pears.

$a:o=4:6$
⇒ $(a)/(o)= (4)/(6)$
⇒ $a= (4)/(6)o$

$o:p=8:1$
⇒ $(o)/(p)= (8)/(1)$
⇒ $o= 8p$

Therefore:
$a= (4)/(6)*8p =16/3p$

Now, if $a+o+p=172$ , then:
$(16)/(3)p +8p+p=172$
$(16)/(3)p +9p172$

Since $9= (9)/(1) = (27)/(3)$ , 9p can be expressed as 27/3p:
$(16)/(3)p+ (27)/(3)p=172$
$(43)/(3)p =172$
⇒ $p =172* (3)/(43)$
⇒ p = 12
There are 12 pears.

Since o = 8p, o = 96:
o = 8 × 12 = 96
There are 96 oranges.

Since $a= (16)/(3)p$ , a = 64:
$a= (16)/(3) *12=16*4=64$
There are 64 apples.

Therefore, there are 64 apples, 96 oranges, and 12 pears.

Simplify.9y+11z+7y−4z9y+11z+7y−4z

2y + 7z

16y + 7z

23yz

16y + 15z