MATHEMATICS HIGH SCHOOL

Solve the logarithm. show steps.

Answers

Answer 1

Answer: $log_82+log_84x^2=1;\ D:x^2 > 0\Rightarrow x\neq0\n\nlog_8(2\cdot4x^2)=log_88^1\n\nlog_88x^2=log_88\iff8x^2=8\ \ \ |both\ sides\ /:8\n\nx^2=1\iff x=-1\ or\ x=1.\n\nSolutions:x=-1\ \vee\ x=1.$

Answer 2

Answer: $\log_82+\log_84x^2=1\n D:4x^2>0\n D:x\in\mathbb{R}\n \log_88x^2=1\n 8^1=8x^2\n x^2=1\n x=-1 \vee x=1\n$

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Is 9 rational or irrational?

Answers

Answer:

9 is a rational number.

Step-by-step explanation:

Answer:

irrational

Step-by-step explanation:

How the number 9 is irrational is that irrational numbers are numbers that are not expressed as fractions or decimals. So some examples of irrational numbers is 1,2,6,22,12,9

can I get brainlest?

How is the graph of y=-2(3)^x+4 translated from the graph of y=2(3)^x

Answers

From the graph of y=2(3)^x:
The negative sign on the coefficient means a reflection across the x-axis. The plus 4 means shifted up 4 units.

It is reflected across the x-axis and the constant multiplicative rate is increased by four, downwards

Which expressions result in a positive number? Choose all answers that are correct.

A.

B.
–5 – (–5.1)

C.
14 • (–3)

D.
3 + (–7)

Answers

Expression B results in a positive number

Cheerios

Solve for w k=2b-5w/3k

Answers

Answer:

b = $(2b - 3k^(2) )/(5)$

Step-by-step explanation:

To solve for w in this equation;

k = $(2b - 5w)/(3k)$

This implies we have to make w the subject of the formula.

To make w subject of the formula, first we cross multiply.

3k × k = 2b - 5w

3k² = 2b -5w

Now we will subtract 2b from both- side of the equation

3k² - 2b = -5w

we want to make the right hand side of the equation positive, to do that , we will just multiply through by minus sign. The equation becomes;

-3k² + 2b = 5w

We can rearrange the equation;

2b - 3k² = 5w

5w = 2b - 3k²

Then we will now divide both-side of the equation by 5

$(5w)/(5) = (2b - 3k^(2) )/(5)$

In the left side of the equation, the 5 at the numerator will cancel out the 5 at the denominator.

Hence;

w = $(2b - 3k^(2) )/(5)$

$k = (2b - 5w)/(3k)$
$3k^(2) = 2b - 5w$
$3k^(2) + 5w = 2b$
$5w = 2b - 3k^(2)$
$w = (2)/(5)b - (3)/(5)k^(2)$

Find the sum of the arithmetic sequence.

-10, -7, -4, -1, 2, 5, 8

Answers

Answer:

+3 every time or the total?

Or is it 18? U specify which

HELP ASAP Solve log7 b > 2. Question 18 options: b > 7 b > 49 b > 2–7 b > 14

Answers

Answer: Second Option

$b > 49$

Step-by-step explanation:

We have the following expression:

$log_7(b) > 2$

We have the following expression:

To solve the expression, apply the inverse of $log_7$ on both sides of the equality.

Remember that: $b ^ {log_b (x)} = x$

So we have to:

$7^(log_7(b)) > 7^2$

$b > 7^2$

$b > 49$

The answer is the second option

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Select the correct answer. The sum of two numbers is -18. If the first number is 10, which equation represents this situation, and what is the second number? A. The equation that represents this situation is 10 − x = -18. The second number is 28. B. The equation that represents this situation is 10 + x = -18. The second number is -28. C. The equation that represents this situation is x − 10 = -18. The second number is -8. D. The equation that represents this situation is -10 + x = -18. The second number is -8.

Subtract: 3x^2 - 7x + 4 from 5x^2 - 3x + 8.