Moons orbit planets and planets orbit theSun. Is Kepler’s constant the same for both
circumstances?

Answers

Answer 1

Answer: What Kepler's constant ? ? ! ?

The only constant in Kepler's laws is in the third one, where it says something to the
effect that (square of a body's period) / (cube of its distance from the central body)
is a constant.

That means it's a constant for multiple little ones orbiting the same central body.
But it's not the same constant for other central bodies.

It's one constant for the planets, asteroids, and comets orbiting the sun.

It's a different constant for the moon, TV satellites, weather satellites,
and military satellites orbiting the Earth.

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A mass that weighs 8 lb stretches a spring 24 in. The system is acted on by an external force of 4 sin 4t lb. If the mass is pulled down 6 in. and then released, determine the position of the mass at any time. Determine the first four times at which the velocity of the mass is zero
This diver has just jumped up from the end of the diving board. After she dives down and is falling toward the water, she’ll have kinetic energy, or the energy of moving matter. But even as she is momentarily stopped high above the water, she has energy. Do you know why?

When there is no air resistance, objects of different masses dropped from rest?

Answers

Reach the ground at the same time

The parietal lobe is the portion of the cerebral cortex located below the temporal lobe.Please select the best answer from the choices provided

T
F

Answers

Answer:

False

Explanation:

Please see the attached file

Answer: the answer is false

Explanation:

I just took the test.

Which of the following is most closely related to an activated complex?a. rate limiter
b. energy barrier
c. collision group
d. transition state

Answers

Among the choices above, the one that is most closely related to an activated complex is the transition state. The answer is letter D. This formation forms quickly and does not stay in a way compound is. It usually forms during the enzyme – substrate reaction.

Millikan measured the electron's charge by observing tiny charged oil drops in an electric field. Each drop had a charge imbalance of only a few electrons. The strength of the electric field was adjusted so that the electric and gravitational forces on a drop would balance and the drop would be suspended in air. In this way the charge on the drop could be calculated. The charge was always found to be a small multiple of 1.60 × 10-19 C. Find the charge on an oil drop weighing 1.00 × 10-14 N and suspended in a downward field of magnitude 2.08 × 104 N/C.

Answers

Answer:

$4.8\cdot 10^(-19) C$

Explanation:

For a drop in equilibrium, the weight is equal to the electric force (in magnitude):

$W = F_e$

where here we have

$W=1.00\cdot 10^(-14)N$ is the weight of the drop

$F_e$ is the magnitude of the electric force, which can be rewritten as

$F_e = qE$

where

q is the charge of the oil drop

$E=2.08 \cdot 10^4 N/C$ is the magnitude of the electric field

Substituting into the equation and solving for q, we find the charge of the oil drop:

$q=(W)/(F_e)=(1.00\cdot 10^(-14)N)/(2.08\cdot 10^4 N/C)=4.8\cdot 10^(-19) C$

Why does a vibraing simple pendulum not produce any sound

Answers

Human ear can hear the lowest frequency about 20 Hz, this is 20 vibrations per second. Vibrations of pendulum are very small and frequency is less than 20 Hz, so we can't hear it.

It does, but the sound is at a frequency that's too low for you to hear.
If you could build a pendulum short enough so that it made 20 or more
complete swings every second, THEN you'd begin to hear sound from it.

39WERELAIS
01:21:51
Which type of reaction is C2H2011 - 12C + 11H202
O synthesis
decomposition
O oxidation
combustion