Name the physical quantity measured by the area under velocity time graph?

Answers

Answer 1

Answer: The area under a speed-time graph, between two time marks and between the
x-axis and the graph line, is exactly the distance traveled during that time.

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The solar system formed from the A. collapse of an interstellar cloud. B. grouping together of asteroids. C. explosion of an interstellar sun. D. collision of two massive stars
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Hat is the kinetic energy of a 1.0-kg billiard ball that moves at 5.0 m/s? A.
5.0 J

B.
6.5 J

C.
10.0 J

D.
12.5 J

Answers

Kinetic energy is the energy that a body possesses by being in motion. It is calculated by the expression:

Kinetic Energy = 1/2 (mv²)
Kinetic Energy = 1/2 (1 kg) (5m/s)²
Kinetic Energy = 12.5 J

Therefore, the correct answer from the choices above is option D.

A roller coaster starts down a hill at 10 m/s. Three seconds later, its speed is 32 m/s. What is the roller coaster’s acceleration?Question 1 options:

-7.3 m/s

-7.3 m/s2

3 m/s

3 m/s 2
Save
Question 2 (2 points) Question 2 Unsaved
Natalie accelerates her skateboard along a straight path from 4 m/s to 0 m/s in 25.0 s. Find the acceleration.

Question 2 options:

-6.25 m/s2

0.16 m/s2

-0.16 m/s2

6.25 m/s2

Save
Question 3 (2 points) Question 3 Unsaved

Find the average acceleration of a northbound subway train that slows from 12 m/s to 9.6 m/s in 0.9 s

Question 3 options:

-2.7 m/s2

2.7 m/s2

-2.7 m/s

2.7 m/s

Save
Question 4 (2 points) Question 4 Unsaved
What is a chicken’s rate of acceleration that speeds up from 4 mph (mi/h) to a top speed of 9 mi/h in 0.5 hr?

Question 4 options:

2.5 mi/h/s

-2.5 mi/h/s

2.5 mi/h2

10 mi/h2

Save
Question 5 (2 points) Question 5 Unsaved
Which units would be appropriate to measure Acceleration?

Question 5 options:

m/s with direction

m/s2

Kg (m/s)

m/s

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Answers

1) a = Δv/Δt
a = (32-10)/3
a = 7.33 m/s²

2) a = (0 - 4)/25
a = -0.16 m/s²

3) a = (9.6 - 12) / 0.9
a = -2.7 m/s²

4) a = (9-4)/0.5
a = 10 mi/h²

5) m/s²

How much force is needed to stop a 90-kg soccer player if he decelerates at 15 m/s^2?A. 15 N
B. 6 N
C. 135 N
D. 1,350 N

Answers

We have: F = m×a
Here, m = 90 Kg
a = 15 m/s²

Substitute their values into the expression:
F = 90 × 15
F = 1350 N

In short, Your Answer would be Option D

Hope this helps!

According to the information in your study unit, which of the following locations requires the highest illuminance? A. A residential stairway
B. A school locker room
C. A bank lobby
D. A study area

Answers

The correct answer is letter D. A study area. According to the information in your study unit, the location that requires the highest illuminance is the study room because it is the place the students can stay to study. The more brighter the place is, the more people are using that area.

A frictionless, massless pulley is attached to the ceiling, in a gravity field of 9.81 m/s2. Mass M2 is greater than mass m1. The quantities Tn and g are magnitudes.a.The center of mass accelerates.
b.T1 is ..... M1g.
c. T3 is ..... m1g + M2g
d.T1 is ..... T2
e.The magnitude of the acceleration of M2 is ..... the magnitude of the acceleration on m1.
f. T1 + T2 is ..... T3

Answers

Answer:

a. center of mass acceleration supposed to be acceleration due to gravity, 9.81 m/s^2,

b. T1 = 9.81m1 N; c. T3 =9.81(M1+M2) N; d. T3-T1, e. (T3-T1)/M2; f. (M1+M2)T3/M3

Explanation:

Final answer:

In this frictionless, massless pulley system, the center of mass accelerates downward with an acceleration equal to the acceleration due to gravity. The tension in the string connected to mass M1 is equal to M1g, and the tension in the string connected to mass M2 is equal to m1g + M2g. The magnitudes of the accelerations of M1 and M2 are equal, and the sum of the tensions T1 and T2 is equal to the tension T3.

Explanation:

a. The center of mass accelerates: When considering the system as a whole, the acceleration of the center of mass is determined by the net external force acting on the system. In this case, the only external force is the force due to gravity. Therefore, the center of mass accelerates downward with an acceleration equal to g, the acceleration due to gravity.

b. T1 is equal to M1g: The tension in the string connected to mass M1 is equal to the weight of M1, which is given by the formula T1 = M1g.

c. T3 is equal to m1g + M2g: The tension in the string connected to mass M2 is equal to the sum of the weights of M1 and M2, which is given by the formula T3 = m1g + M2g.

d. T1 is equal to T2: Since the pulley is assumed to be frictionless and massless, the tension in the string connected to mass M1 is the same as the tension in the string connected to mass M2.

e. The magnitude of the acceleration of M2 is equal to the magnitude of the acceleration on M1: This is due to the constraint imposed by the tension in the string. Since the tension in the string connecting M1 and M2 is the same, their accelerations must also be the same.

f. T1 + T2 is equal to T3: The sum of the tensions T1 and T2 is equal to the tension T3, as the total force acting on mass M2 is equal to the sum of the individual tensions.

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Your physics teacher is giving you a special gift a box of mass 20 kg with a mystery surpise insie .the box is placed on a frictionsed table .what is the weigth of the box and normal reaction over it by the table ?