If air is cooled to the point at which its water vapor condenses, it has reached itsa. dew point.
b. triple point.
c. lambda point.
d. freezing point.

Answers

Answer 1
Answer: a. dew point, i surlly :)

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Persamaan kimia bagi magnesium

Answers

English please ..I don't understand this.

NaOH  + H2SO4 =NaOH + HNO3  =
Cu(OH)2 + HCl =
                H2SO4 =       
                HNO3 =

Answers

2NaOH+H_2SO_4\Rightarrow\ Na_2SO_4+2H_2O\n NaOH+HNO_3\Rightarrow\ NaNO_3+H_2O\n Cu(OH)_2+2HCl\Rightarrow\ CuCl_2+2H_2O\n Cu(OH)2+H_2SO_4\Rightarrow\ CuSO_4+2H_2O\n Cu(OH)_2+2HNO_3\Rightarrow\ Cu(NO_3)_2+2H_2O

Q. 8 Normally, the pH of the human body is fixed in a very narrow range between 7.35 and 7.45. Apatient with an acidotic blood pH of 7.3 may be treated with an alkali such as sodium bicarbonate.
Why would this treatment raise the pH of the blood? Can you please explain it?

Answers

correct answer is( respiratory alkalosis) is a primary decrease in  pco2 with or without compensatory decrease  in h2o3 

Final answer:

When a person has acidosis, their blood is too acidic. Sodium bicarbonate, an alkali, can help by producing hydroxide ions that neutralize excess hydrogen ions, which are responsible for the acidity. This action decreases the acidity of the blood, thereby raising its pH.

Explanation:

The human body's pH level is crucial to maintaining good health. When a person has acidosis, the blood is too acidic, and the pH is often less than the normal range of 7.35 to 7.45. Sodium bicarbonate, a type of alkali, can help treat this condition.

Alkalis such as sodium bicarbonate are basic compounds. When they dissolve in water, they produce hydroxide ions (OH-). These ions can neutralize the excess hydrogen ions (H+) in our body, which are responsible for creating an acidic environment. As a result of this neutralization, the amount of H+ in the body decreases, thus leading to an increase in blood pH, making it less acidic (more alkaline).

So, to put it in simpler terms, the sodium bicarbonate raises the blood's pH by reducing the amount of acid in it - making the blood less acidic and more alkaline.

Learn more about Sodium bicarbonate and blood pH here:

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How does the arrangement of the particles in a solid compare to that of a liquid? ( The arrangement of a solid's and a liquid's particles is the same.

The particles in a solid are farther apart than the particles in a liquid.

The particles in a solid are closer together than the particles in a liquid.

The arrangement of a solid's and a liquid's particles will depend on the mass of the substance.

Answers

The particles in a solid are closer together than the particles in a liquid.
The correct answer is C.

Find the number of kilometers in 92.25m.

Answers

The length measurement in kilometers will be -

92.25 x 10⁻³ Kilometers.

We have length measurement of 92.25 m.

We have to determine the number of kilometers in this much length.

How many maters are there in one kilometer ?

In 1 km there are 1000m

According to the question -

Length measurement = L = 1 meter

In kilometers, the length will be = 1 /1000 x 92.25 =

92.25 x 10⁻³ Kilometers.

Therefore, the length measurement in kilometers will be -

92.25 x 10⁻³ Kilometers.

To solve more questions on Unit conversions, visit the link below-

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1000m = 1km
92.25m= ?

We cross multiply
92.25/1000
= 0.09225

Therefore, 92.25m = 0.09225km

How many days are required for 200. grams of radon-222 to decay to 50.0 grams?(1) 1.91 days (3) 7.64 days(2) 3.82 days (4) 11.5 days

Answers

The answer is: 3) 7.64 days.

The most stable isotope of radon (Rn) is radon-222 with a half-life of 3.82 days.

After first half life (3.82 days) = 0.5 · 200 g.

After first half life (3.82 days) = 100 g of radon-222.

After second half life (7.64 days) = 0.5 · 100 g.

After second half life (7.64 days) = 50 g of radon-222.

Half-life is the time required for a quantity (in this example number of radioactive nuclei of radon-222) to reduce to half its initial value and is independent of initial concentration.

The answer is (3) 7.64 days. The remaining mass of radon-222 is one fourth of the original mass, so two half lives have elapsed (because one half time one half equals one fourth). Each half life of radon-222 is about 3.82 days, so the total time elapsed is 3.82 * 2 = 7.64 days