A(n) ________ is a shorthand notation for repeated multiplication of the same factor.

Answers

Answer 1
Answer:
An exponent is a shorthand notation for repeated multiplication of the same factor. For instance 54 means 5*5*5*=625.
Answer 2
Answer: An exponent is I believe

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There are 20 pieces of fruit in a bowl and 8 of them are apples. What percentage of the pieces of fruit in the bowl are apples?
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Which statements are true regarding the area of circle D? Select two options. The area of the circle depends on the square of the radius.
The area of circle D is 36Pi centimeters squared.
The area of circle D is 324Pi centimeters squared
The area of the circle depends on the square of pi.
The area of the circle depends on the central angle.

Answers

Answer:

The ratio of the measure of central angle PQR to the measure of the entire circle is 1/8

The area of the shaded sector depends on the length of the radius.

The area of the shaded sector depends on the area of the circle.

Step-by-step explanation:

During a recent winter, the ratio of deer to foxes was 7 to 3 in a town. If there was 210 foxes in the town, what was the number of deer in the town?

Answers

(7)/(3) = (x)/(210)
Cross multiply and get 1470/3
Your final answer is 490 deer.

Isabella has 7 yards of ribbon to make bows. Each bow is made from a peace of ribbon that is 1/2 yard long. How many bows can Isabella make?

Answers

Answer:

14 bows

Step-by-step explanation:

Isabella has 7 yards of ribbon to make bows. Each bow is made from a peace of ribbon that is 1/2 yard long. How many bows can Isabella make?

The above question is calculated as:

1/2 yard of ribbon = 1 bow

7 yards of ribbon = x bows

We cross multiply

1/2 yard of ribbon × x bows = 7 yards of ribbon × 1 box

x bows = 7 yards of ribbon × 1 box/1/2 yard of ribbon

x bows = (7 ÷ 1/2 ) bows

x bows = 7 × 2 bows

= 14 bows

Therefore, Isabella can make 14 bows

Amanda’s dad is twice as old as she is today. The sum of their ages is 66. Find the ages of Amanda and her dad.

Answers

Let amanda's age be x and her dad's age be y.

Amanda’s dad is twice as old as she,  therefore 2x=y

The sum of their ages is 66, therefore x+y=66

x+y=66

2x=y,

substitute.

2x+x=66

3x=66

Divide.

x=22.

plug it back in, 22+y=66, y=44.

Amanda's age is 22 and her dad's age is 44.

How does changing the scale change the distance represented?

Answers

The correct answer is:

It does not.

Explanation:

The scale of a graph just tells us how many units are between numbers. This does not change the overall distance represented.

For example, I can have two graphs on which the x-axis goes to 60. On one graph, I can count by 10s for my scale, while the other graph uses 5s. While the scales are different, the same distance is represented.

It does not. The fact that the scale may change, however, the distance between two object does not change at all. For an example, the distance between cities may stay the same while changing the scale. Therefore, it is a fact that the changing of the scale does not change the distance at all.

Let \( A \) and \( B \) be events with \( P(A)=1 / 3 \) and \( P(B)=2 / 3 \). Let \( N \) be the number of events from among \( A \) and \( B \) that occur. (For instance, if \( A \) occurs but \( B \) does not, then \( N=1 \).) Suppose that the occurrence of events in \( A \) and \( B \) are independent. Find, for example, the probability that no events occur.

Answers

Answer:

( 2/9 )

Step-by-step explanation:

Okay, so since the events A and B are independent, the probability that both of them do not occur is the product of their individual probabilities of not occurring.

The probability of event A not occurring, denoted as ( P(A') ), is equal to 1 minus the probability of A occurring. Similarly, the probability of event B not occurring, denoted as ( P(B') ), is equal to 1 minus the probability of B occurring.

So, ( P(A') = 1 - P(A) = 1 - 1/3 = 2/3 ) and ( P(B') = 1 - P(B) = 1 - 2/3 = 1/3 ).

Since A and B are independent, the probability that both A and B do not occur is simply the product of their individual probabilities of not occurring:

[ P(N = 0) = P(A' cap B') = P(A')P(B') = (2/3) times (1/3) = 2/9 ]

So, the probability that no events occur is ( 2/9 ).

Hope this helps! :)