MATHEMATICS HIGH SCHOOL

The association strategy is used to___________informationa. Analyze and evaluate
c. Forget
b. Memorize
d. Define

Answers

Answer 1
Answer:

Answer: Option 'B' is correct.

Step-by-step explanation:

The association strategy is used to memorize information.

Because if we memorise the information then, we are able to associate it with something related. And we can go for the association strategy.

And if we know that one thing can be associated with the other thing. then we can easily memorise the information.

Therefore, association and memorizing is inter- related.

Hence Option 'B' is correct.
Answer 2
Answer: it memorize the imformation

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What are the lengths of the legs of a right triangle in which one acute angle measures 19o and the hypotenuse is 15 units long?

Answers

x,y-\ lengths\ of\ legs\n\nsin19^\circ=(x)/(15)\n\n sin19^\circ*15=x\n\n0,32*15=x\n\nx=4,8\n\n y^2+(4,8)^2=15^2\n\ny^2=225-23,04\n\n y^2=201,96\n\ny=14,2\n\nLegs\ are\ equalt\ to:\ 4,8 \ and\ 14,2.

Answer:

For plato users the correct option is D.

Step-by-step explanation:

D. 4.9 units, 14.2 units

What does 5^(3*5^(-4)) equal plus steps

Answers

If you simplify the expression, you get 5 3/625.
In decimal form, your answer would be 1.00775521...
5^3(5^−4)

=5^3(1/625)
=5^3/625
=1.007755

What two numbers multiply to 44 and add up to 12?

Answers

This pattern of question is always coming up. Since we can't easily guess, then let us set up simultaneous equation for the statements.

let the two numbers be x and y.

Multiply to 44.      x*y = 44 ..........(a)

Add up to 12.      x + y = 12 .........(b)

From (b)

y = 12 - x .......(c)

Substitute (c) into (a)

x*y = 44

x*(12 - x) = 44   

12x - x² = 44

-x² + 12x = 44

-x² + 12x - 44 = 0.       

Multiply both sides by -1

-1(-x² + 12x - 44) = -1*0

x² - 12x + 44 = 0.   

This does not look factorizable, so let us just use quadratic formula

comparing to ax² + bx + c = 0, x² - 12x + 44 = 0,  a = 1, b = -12, c = 44 

x = (-b + √(b² - 4ac)) /2a   or (-b - √(b² - 4ac)) /2a


x = (-(-12) + √((-12)² - 4*1*44) )/ (2*1)    

x = (12 + √(144 - 176) )/ 2

x = (12 + √-32 )/ 2

√-32 = √(-1 *32) = √-1 * √32 = i * √(16 *2) = i*√16 *√2 = i*4*√2 = 4i√2

Where i is a complex number.  Note the equation has two values. We shall include the second, that has negative sign before the square root.

x = (12 + √-32 )/ 2      or     (12 - √-32 )/ 2   

x = (12 + 4i√2 )/ 2              (12 - 4i√2 )/ 2 

x = 12/2 + (4i√2)/2                12/2 - (4i√2)/2

x = 6 + 2i√2            or         6 - 2i√2

Recall equation (c):

y = 12 - x, When x = 6 + 2i√2,  y = 12 - (6 + 2i√2) = 12 - 6 - 2i√2 = 6 - 2i√2

When x = 6 - 2i√2,  y = 12 - (6 - 2i√2) = 12 - 6 + 2i√2 = 6 + 2i√2


x = 6 + 2i√2,  y = 6 - 2i√2

x = 6 - 2i√2,  y = 6 + 2i√2

Therefore the two numbers that multiply to 44 and add up to 12 are:

6 + 2i√2 and 6 - 2i√2
xy=44\n x+y=12\n\n xy=44\n x=12-y\n\n (12-y)y=44\n 12y-y^2=44\n y^2-12y+44=0\n y^2-12y+36+8=0\n (y-6)^2=-8

No solutions in real numbers.

In complex numbers:
(y-6)^2=-8\n y-6=-√(-8) \vee y-6=√(-8)\n y=6-2\sqrt2 i \vee y=6+2\sqrt2 i\n\n x=12-(6-2\sqrt2i) \vee x=12-(6+2\sqrt2i)\n x=12-6+2\sqrt2i \vee x=12-6-2\sqrt2i\n x=6+2\sqrt2i \vee x=6-2\sqrt2i

These numbers are 6-2\sqrt2i and 6+2\sqrt2i.

Solve the inequality
3(3F − 2) > 6F − 4

Answers

3 (3F - 2) > 6F - 4

Expand the left side:            9F - 6 > 6F - 4

Add 6 to each side:              9F      > 6F + 2

Subtract 6F from each side:  3F > 2

Divide each side by 3 :            F > 2/3 .

Suppose U=(-1,-2,-3,4,5,6,7,8) is the universal set and X=(-2,4,6,8) what is x?

Answers

Ir results that X is a subset of U.

what is the decimal sign-and-magnitude value of the 8-bit number represented in 2's complement by 11010011?

Answers

Answer:

-45.

Step-by-step explanation:

The decimal value is negative because the first digit is a '1'.

11010011

 First we subtract 1 :

11010011

           -1

11010010

Now we replace each 1 by 0 and 0 by 1:

= 00101101

In decimal this is - (1 + 2^2 + 2*3 + 2^5)

= -45.
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