What is imagery?writing or speech that is not intended to carry literal meaning
a technique in which something simultaneously represents itself and something else
a figure of speech that makes a comparison between two objects
words that trigger the imagination to remember by appealing to the five senses

Answers

Answer 1

Answer:

Correct answer choice is :

D) Words that trigger the imagination to remember by appealing to the five senses

Explanation:

Imagery, in a literary text, is an author's use of clear and expressive voice to add intensity to their work. It advances to human senses to increase the reader's understanding of the work. Powerful forms of imagery involve all of the senses. Basically, there are five types of imagery, each corresponding to one of our senses, visual, auditory, kinesthetic olfactory, and gustatory. The key to good imagery is involving all five senses.

Answer 2

Answer: Imagery is almost like a film being played in the readers mind when reading literature. So on that note, I think the last one, 'words that trigger the imagination to remember by appealing to the five senses', is the best choice.

I hope this helps!

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Forces contribute to the net force on a car rolling down a ramp?Forces contribute to the net force on a car rolling down a ramp.

a. Which force supports the car’s weight? ______________________________
b. Which force accelerates the car down the ramp? ______________________________
c. Which force acts against the motion of the car? ______________________________

Answers

Answers

1) Reaction

2) Gravitational force

3) Frictional force

Explanation

Reaction is directly opposite and equal to action(normal force). The normal force is the weight. So we can say that reaction supports the weight of the car.

Objects fall downwards due to acceleration due to gravity. The acceleration force is provided by the gravitational force. The car is accelerated downwards by the gravitational force.

Frictional force is the force that opposes relative motion between two bodies. When iar is involved, we call it viscosity. So the force that acts against the motion of the car is friction.

a. the normal force is the ground pushing up on the car
b. gravity accelerates the car down toward the earth
c. friction and air resistance act against the motion

What’s the kinetic energy of the object? Use .Erica is competing in the shot put event at a track meet. She hurls a shot with a mass of 4 kilograms at a speed of 9 meters/second. The shot’s kinetic energy is joules.

Answers

The kinetic energy of an object varies directly with the square of the speed of an object. The required kinetic energy of the shot is f 162 J.

What is Kinetic Energy?

The energy possessed by an object by its motion is known as the object's kinetic energy. It depends on the speed and mass of the given object.

Given data -

The mass of shot put is, m = 4 kg.

The speed of shot put is, v = 9 m/s.

The mathematical expression for the kinetic energy of the shot put is,

$KE = (1)/(2) m v^(2)$

Solving as.

$KE = (1)/(2) * 4 * 9^(2)\n\nKE = 162 \;\rm J$

Thus, we can conclude that the required kinetic energy of the shot is of 162 J.

Learn more about the kinetic energy here:

brainly.com/question/999862

Answer:

We have: K.E. = mv² / 2

here, m = 4 Kg

v = 9 m/s

Substitute their values into the expression:

K.E. = (4)(9)² / 2

K.E. = (4)(81) / 2

K.E. = 324 / 2

K.E. = 162 Joules

Explanation:

In short answer: it would be K.E.=162 Joules

How do you calculate the initial speed given time and displacement?The question is: The longest kick in CFL history was 83.2m. If the ball remained in the air for 4.12s, determine its initial speed.
I calculated it several times and got the same answer, 40.38m/s, but the textbook says it's 28.6m/s.

Answers

Let's first find the velocity in the x-direction which is constant.
$d = vt \n v = (d)/(t) \nv = (83.2m)/(4.12s) \n v= 20.2m/s$

Now, we need the velocity in the y-direction
$d = v_(o)t + (1)/(2)a t^(2) \n d - (1)/(2)at^(2) = v_(o)t\nv_(o) = (0 - (1)/(2)(-9.81)(4.12)^(2))/(4.12)\nv_(o) = 20.2m/s$

Finally, we need to put the two velocities together using pythagorean theorem
$v_(t)^(2) = v_(x)^(2) + v_(y)^(2)$
$v_(t) = \sqrt{20.2^(2) + 20.2^(2)}$
v = 28.6m/s

The mass of a star can be determined by studyinga. the wavelength of light emitted by the star.
b. the color of the star.
c. Kepler's laws.
d. binary star systems.

Answers

The correct answer for the question that is being presented above is this one: "a. the wavelength of light emitted by the star." The mass of a star can be determined by studying the wavelength of light emitted by the star. It also has something to do with the gravitational force that it exerts.

Answer:

D. Binary Star Systems

Explanation:

A speedy rabbit is hopping to the right with a velocity of 4.0 \,\dfrac{\text m}{\text s}4.0 s m 4, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction when it sees a carrot in the distance. The rabbit speeds up to its maximum velocity of 13 \,\dfrac{\text m}{\text s}13 s m 13, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction with a constant acceleration of 2.0 \,\dfrac{\text m}{\text s^2}2.0 s 2 m 2, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction rightward.

Answers

Answer: 38.25 m

Explanation:

In this situation we need to find the distance $d$ between the rabbit and the carrot, and we can use the following equation, since the rabbit's acceleration is constant:

$V^(2)=V_(o)^(2) + 2ad$ (1)

Where:

$V=13 m/s$ is the rabbit's maximum velocity (final velocity)

$V_(o)=4 m/s$ is the rabbit's initial velocity

$a=2 m/s^(2)$ is the rabbit's acceleration

$d$ is the distance between the rabbit and the carrot

Isolating $d$ :

$d=(V^(2)-V_(o)^(2))/(2a)$ (2)

$d=((13 m/s)^(2)-(4 m/s)^(2))/(2(2 m/s^(2)))$ (3)

Finally:

$d=38.25 m$

Answer:

4.5s

Explanation:

Cause that's what it says on my test hints

Heisenberg's Uncertainty Principle states that we cannot simultaneously measure both the position and momentum of an object better than a certain accuracy. This limitation is not a consequence of imperfect technology, but is a fundamental law. It applies to all objects -- photons, electrons, baseballs, etc.. A highly monochromatic, continuous beam of laser light of wavelength 470 nm passes through an electro-optic shutter. The shutter opens and closes in a time interval of Δt = 90 ps . After passing through the shutter to what uncertainty, Δx, have the photons been localized?

Answers

For this specific problem, the photons have been localized toDx = 0.027muncertainty. I am hoping that this answer has satisfied yourquery about and it will be able to help you, and if you’d like, feel free toask another question.

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