an eagle flies from its perch in a tree to the ground to capture it's prey. describe it's energy transformations.

Answers

Answer 1

Answer: The eagle is on top of the tree. It is not in motion so it has potential energy.

It has the potential of falling and having energy.

Once the Eagle falls from the tree it is now moving and has Kinetic energy.

It's energy has transferred from Potential energy to Kinetic Energy.

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HELP ASAP PLEASE PHYSICS 1.How much charge is carried across a 5.5 A current over a time of 8.3 seconds? (1 point)
45.65 C
52.79 C
78.11 C
20.05 C

2.A current of 1.90 A flows through a wire. How many electrons pass through that wire in 1 second? The charge of an electron is 1.602 x 10^-19 C (1 point)
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2.01 x 10^18 electrons
1.04 x 10^20 electrons
1.19 x 10^19 electrons

3.A battery of voltage 9.0 V produces a current of 17.5 mA across a circuit. What is the resistance of the circuit? (1 point)
433 Ohms
514 Ohms
701 Ohms
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4.A battery is marked as having a voltage of 12.0 V and is connected to a circuit that has a resistance of 5.0 Ohms. If the terminal voltage is 8.75 V, what is the internal resistance of the circuit? (1 point)
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256 Ohms

8.What is the equivalent resistance in this circuit? (1 point)

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9.What is the equivalent resistance in this circuit? (1 point)

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Answers

Answer:

1. 45.65

2. 1.19x10^19

3. 514OHM

4. 2.45 ( NOT 1.86 OR 1.36)

6. 20.06A

7. 206 ohms

8. 13 Ohms

9. 2 ohms

10. 0.051 ( NOT 0.036 OR 0.089)

Explanation:

I've struggled with both problems 4 and 10

Answer: did you get the answers?

Explanation:

determine the magnitude and direction of the resultant for a combination of the vectors A: 10.1m, 60 degrees B: 7.3m, 275 degrees

Answers

Answer:

5.87 m, 75.5°

Explanation:

Let's say C is the resultant vector.

The x component is the sum of the x components of A and B.

Cx = Ax + Bx

Cx = 10.1 cos 60° + 7.3 cos 275°

Cx = 5.69

The y component is the sum of the y components of A and B.

Cy = Ay + By

Cy = 10.1 sin 60° + 7.3 sin 275°

Cy = 1.47

The magnitude is found with Pythagorean theorem, and the angle is found with trigonometry.

C² = Cx² + Cy²

C² = 5.69² + 1.47²

C = 5.87

θ = atan(Cy / Cx)

θ = atan(5.69 / 1.47)

θ = 75.5°

Mechanical energy is the sum of kinetic energy and all forms of potential energy that an object has.Please select the best answer from the choices provided
t or f

Answers

Answer:

the mechanical energy of an object can be the result of its motion (i.e., kinetic energy) and/or the result of its stored energy of position (i.e., potential energy). The total amount of mechanical energy is merely the sum of the potential energy and the kinetic energy.

Answer:

Explanation:

The chemical formula for water, H2O, means that each water molecule contains

Answers

2 hydrogen molecules and one oxygen molecule

Energy stored in the nucleus of an atom is called

Answers

nuclear energy because it holds atoms together.

Atomic Energy or Nuclear Energy

a person pushing a stroller starts from rest, uniformly accelerating at a rate of 0.500 m/s2. What is the velocity of the stroller after it has traveled 4.75 m ?

Answers

Answer:

Approximately $2.18 m\cdot s^(-1)$ .

Explanation:

Consider one of the equations for constant acceleration ("SUVAT" equations)

$v^(2) - u^(2) = 2 \; a \cdot x$ ,

where

$v$ is the final velocity of the object,
$u$ is the initial velocity of the object,
$a$ is the acceleration of the object, and
$x$ is the distance that the object had traveled while its velocity changed from $u$ to $v$ .

Note that unlike other SUVAT equations, this one does not ask for the time required for the speed of the object to change from $u$ to $v$ . Since in this problem, time isn't given, this time-less equation would particular useful.

Here

$v$ the final velocity needs to be found.
$u = 0$ for the stroller started from rest.
$a =\rm 0.500 \;m \cdot s^(-2)$ is the acceleration of the stroller, and
$x = \rm 4.75\; m$ is the distance that the stroller traveled while its velocity changed from $u$ to $v$ .

Rearrange the equation to isolate the unknown, $v$ :

$v^(2) = u^(2) + 2 \; a \cdot x$ .

Make sure that all units are standard, so that the unit of the output will also be standard. Apply the equation:

$v = \sqrt{u^(2) + 2 \; a \cdot x} = √(0^2 + 2 * 0.500 * 4.75 )\approx \rm 2.18\; m\cdot s^(-1)$ .

Hence the final velocity will be approximately $\rm 2.18 m\cdot s^(-1)$ .

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