A 50 meter path surrounds a rectangular garden . The width of the garden is two-thirds its length. find its area.

Answers

Answer 1
Answer: w-width\nl-length\n\n2w+2l=50\to w+l=25\nw=(2)/(3)l\n\nsubstitute:\n\n(2)/(3)l+l=25\n\n(5)/(3)l=25\ \ \ \ /\cdot(3)/(5)\n\nl=15\ (m)\n\nw=(2)/(3)\cdot15=10\ (m)\n\nArea:A_{\fbox{ }}=wl\to A_{\fbox{ }}=10\cdot15=150\ (m^2)

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The inner and outer Radii of a cylindrical pipe are 5 cm and 4 cm respectively. find the area of cross section of the pipe. 

Answers

To do this find the area of the inner pipe, and then find the area of the outer pipe, then subtract the larger of the two from the smaller, and that is the area of the cross section

Answer:

28.3 cm²

Step-by-step explanation:

You find the area of the whole section which is 5²π = 25π.

Then you find the area of the empty part which is 4²π = 16π.

Then you subtract to get 9π which is 28.27433388......

= 28.3 cm²

(5,0) is a solution to the equation y = 5x + 5 Question 11 options: True False

Answers

Answer:

False

Step-by-step explanation:

y=5x + 5

0=5 (5)+5

0=10+5

0≠15

False

Red kangaroos can reach speeds up to 50 feet per second. Use the linear graph at the left to answer the questions. What is the change in y-values from Point A to Point B? What is the change in x-values from Point A to Point B? What is the rate of change of the linear function in feet per second?

Answers

we are given points A and B

A=(3,150)

B=(4,200)

we can find points

x1=3 , y1=150

x2=4 , y2=200

(a)

the change in y-values from Point A to Point B is

=y_2-y_1

now, we can plug values

=200-150

=50feet...........Answer

(b)

the change in x-values from Point A to Point B is

=x_2-x_1

now, we can plug values

=4-3

=1second...........Answer

(c)

the rate of change of the linear function in feet per second is

=(y_2-y_1)/(x_2-x_1)

now, we can plug values

=(50)/(1)feet/sec

=50feet/sec.................Answer


The straight line graph indicates that rate of change of the distance traveled with time by the red kangaroo is a constant

  • The change in y-values from point A to point B is 50 feet.
  • The change in x-values from point A to point B is 1 second.
  • The rate of change of the linear function is 50 feet per second.

Reasons:

The y-values at point A = 150 feet

The y-values at point B = 200 feet

Change in y-values from point A to point B, Δy is given as follows;

Δy = y-values at point B - y-values at point A

Δy = 200 feet - 150 feet = 50 feet

Change in y-values from point A to point B, Δy = 50 feet

The x-values at point A = 3 seconds

The x-values at point B = 4 seconds

Change in x-values from point A to point B, Δx is given as follows;

Δx = x-values at point B - x-values at point A

Δx = 4 seconds - 3 seconds= 1 second

Change in x-values from point A to point B, Δx = 1 second.

The rate of change of the linear function is (\Delta y)/(\Delta x), therefore, we have;

Rate \ of \  change \  of \  the  \ linear  \ function = (\Delta y)/(\Delta x) = (50 \ feet)/(1 \ second) = 50 \ feet \ per \ second

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brainly.com/question/12918390

Shureka Washburn has score of 72,67,82, and 79 on her alebra test. Use an inequality to find the scores she must make on the final exam to pass the course with an average of 77 or higher, given that the final exam counts as two test.

Answers

Answer:

x \geq 81

Step-by-step explanation:

Shureka Washburn has score of 72,67,82, and 79 on her algebra test.

Let x be the score on the final exam.

(72+67+82+79+x+x)/(6) \geq 77

=>(300+2x)/(6) \geq 77

=> 300+2x \geq(77)6

=> 300+2x \geq 462

=> 2x \geq 462-300

=> 2x \geq 162

=> x \geq 81

72+67+82+79=300
300/4=75
300+81+81=462
462/6=77


ANSWER X MUST BE GREATER THAN OR EQUAL TO 81

Which of the following describes the translation of

y = |x| to y = |x + 7| - 2

Answers

up 7 units right 2...I'm like 97% positive lol

Which rule represents the translation of hexagon DEFGHI to hexagon D'E'F'G'H'I'?(x, y)→(x - 8, y - 7)

(x, y)→(x - 7, x - 8)

(x, y)→(x - 4, x - 5)

(x, y)→(x - 5, y - 4)

(adding picture in a second)

Answers

We will choose two vertices of hexagon DEFGHI and hexagon D´E´F´G´H´I´:
D ( 2, 5 )  → D´( - 6 - 2 )
E ( 5, 5 )  → E ´( - 3. - 2 )
- 6 = 2 - 8,      - 2 = 5 - 7
- 3 = 5 - 8,      - 2 = 5 - 7
Answer: A) ( x, y )→ ( x-8,  y-7 )

Answer:

A. (x, y)→(x − 8, y − 7)

Step-by-step explanation: