A factory produced a batch of handheld video games, but 4% of the games were found to be defective. If the batch had 250 games in all, how many games in the batch were not defective?

Answers

Answer 1
Answer:

Answer:

240 video games  were not defective in the video game .

Step-by-step explanation:

Formula

Percentage =(Part\ value* 100)/(Total\ value)

As given

A factory produced a batch of handheld video games, but 4% of the games were found to be defective.

If the batch had 250 games in all .

Percentage = 4%

Total value = 250

Put all the values in  the formula

4 =(Part\ value* 100)/(250)

Part\ value =(4* 250)/(100)

Part\ value =(1000)/(100)

Part value = 10

This means number of video games to be defective in the batch are 10 .

Thus

Number of video games in the batch were not defective= Total number of video games in the batch - Number of defective video games in the batch .

Put all the values in the formula

Number of video games in the batch were not defective= 250 - 10

                                                                                          = 240

Therefore 240 video games  were not defective in the video game .

Answer 2
Answer: 250 x 96% (good games) = 240

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Correct answers only please!What is the check digit (d) for the UPC bar code shown below?

A. 2

B. 4

C. 6

D. 8

Answers

Answer:

  D.  8

Step-by-step explanation:

No formula is given, so we use an on-line calculator for the job. The check digit is 8.

Please help on Photo question. Mathematics. Second

Answers

the first solution 
there's no number which > 3 & < 1 
so it is
x>3 
x<1 

Find the discriminant and the number of real roots for this equation 9x^2+12x+4=0

Answers

The discriminant is 0. As the discriminant is 0 it will have equal roots.

And the real root is -2/3.

What is a Quadratic Equation?

In algebra, a quadratic equation is any equation that can be rearranged in a standard form where x represents an unknown, and a, b, and c represent known numbers, where a ≠ zero.

Conclusion: If a = zero, then the equation is linear, no longer quadratic, as there's no ax^2 term.

9x^(2)+12x+4=0

a = 9 ; b = 12; c = 4;

discriminant = Δ = b^(2) - 4ac

             

Δ = 12^(2) - (4*9*4) = 144 - 144 = 0

roots of quadratic equations are [ (-b ± √Δ)/ 2a)]

let roots of eqation are x1 & x2

As discriminant is zero so, x1=x2

x1 = x2 = -b/2a = - 12/(2*9) = -2/3

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Answer:

hello :

9x^2+12x+4=0

a = 9   b = 12    c = 4

the discriminant  Δ = b² - 4ac = 12² - 4(9) (4   ) =144 -  144 = 0

x1 = x2 = - b/2a = -12/18 = - 2/3

  the real root is : - 2/3


Find the mean, median, and mode. If necessary, round your answer to the nearest tenth.{24, 29, 31, 16, 49, 52, 29, 35, 62, 29}

Answers

Answer:

16, 24, 29, 29, 29, 31, 35, 49, 52, 62

Mean: 16 + 24 + 29 + 29 + 29 + 31 + 35 + 49 + 52 + 62 = 356/10 = 35.6

Median: 30

Mode: 29

The sum of two numbers is 14. the larger number minus three times the lesser number -2. what is the lesser number?

Answers

Let's take the 2 numbers are a and b.
a + b =14

if a > b
a - 3b = -2

Subtract both numbers
4b = 16
b = 4

lesser number is 4.

Answer:

The lesser number is y=4

Step-by-step explanation:

Given : The sum of two numbers is 14. the larger number minus three times the lesser number -2.

To find : What is the lesser number?

Solution :

Let the two numbers be x and y,

The sum of two numbers is 14

i.e. x+y=14  ....(1)

Let x be the larger number and y be the smaller number.

So, the larger number minus three times the lesser number -2

i.e.x-3y=-2 ...(2)

Solving equation (1) and (2)

Substitute x from (1) into (2)

x-3y=-2

(14-y)-3y=-2

-y-3y=-2-14

-4y=-16

y=4

Put in equation (1)

x+y=14

x+4=14

x=10

Therefore, The lesser number is y=4 and larger number is x=10.

A rancher has 800 feet of fencing to put around a rectangular field and then subdivide the field into 3 identical smaller rectangular plots by placing two fences parallel to one of the field's shorter sides. Find the dimensions that maximize the enclosed area. Write your answers as fractions reduced to lowest terms

Answers

Let x be the shorter side, and y be the longer side

 

There would be 4 fences along the shorter side, and 2 fences along the longer side

4x + 2y = 800

Rewrite in terms of y:

y = 400 − 2x

 

The area of the rectangular field is

A = x*y

Replace Y with the equation above:

  A = x(400 − 2x)

  A = − 2x^2 + 400x

 

The area is a parabola that opens downward, the maximum area would occur at the parabola vertex.

At the vertex

x = −b/2a

  = −400/[2(−2)]

  = 100

 

y = 400 −2x

y = 400 -2(100)

y = 400-200

y = 200

 

The dimension of the rectangular field that maximize the enclosed area is 100 ft x 200 ft.

The dimension of the rectangular field that maximize the enclosed area is 100 ft by 200 ft.

Application of the vertex of a quadratic equation

The formula for calculating the vertex of  a quadratic equation is given as:

x = -b/2a

From the given question

Let the shorter side be x

Let the longer side of the field be y

If there are 4 fences along the shorter side, and 2 fences along the longer side, hence;

4x + 2y = 800

Write the resultinq equation in slope-intecept form

2y = -4x + 800

y = -2x + 400

y = 400 − 2x

Determine the area of the field

Area = x*y

Substitute the expression above into the area to have:

A = x(400 − 2x)

A = − 2x^2 + 400x

Since the parabola opens downward, the maximum area would occur at the parabola vertex as shown;

x = −b/2a

x = −400/2(-2)

x = 400/4

x = 100

Determine the value of y

y = 400 −2x

y = 400 -2(100)

y = 400-200

y = 200

Hence the dimension of the rectangular field that maximize the enclosed area is 100 ft by 200 ft.

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