Write 63 as a sum of tens and ones
Answers
60+3=63
Final answer:
To represent 63 as a sum of tens and ones, divide 63 into multiples of ten (tens) and the remainder (ones). It will be 6 tens and 3 ones.
Explanation:
The number 63 can be written as a sum of tens and ones. You can do this by dividing the number into tens or multiples of ten and the remaining will be ones.
In case of 63, the largest multiple of ten that is less than 63 is 60 (which is 6 tens) and the remaining number is 3 (which is 3 ones).
Therefore, 63 can be written as the sum of 60 (6 tens) + 3 (3 ones).
So the answer is 6 tens + 3 ones.
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Answers
Answer:
108
Step-by-step explanation:
Answers
ANSWER:
The Greatest common factor (G.C.D) of 9 and 11 is 1
SOLUTION:
Greatest common factor (G.C.D) is the highest number which is factor for both the given numbers.
Here the numbers are 9 and 11.
We can find the Greatest common factor (G.C.D) of 9 and 11 using prime factorization method.
In prime factorization method, each number is written as the multiple of their prime factors, after that, on comparison we can find the Greatest common factor (G.C.D).
The prime factorization of 9 =
The prime factorization of 11 =
We can observe that, greatest common factor for both 9 and 11 is 1.
Hence Greatest common factor (G.C.D) of 9 and 11 is 1
The GCF of 9 and 11 is 1
Answers
luke = 4 presents every 20 minutes
target = 20 presents wrapped per person
y = kx ; where k is the constant rate, x is the number of presents wrapped, y is the total number of minutes spent wrapping x number of presents.
we need to compute for the unit rate of each individual.
Jack: 15 minutes / 3 presents = 5 minutes per present
Luke: 20 minutes / 5 presents = 4 minutes per present
Jack:
y = 5 minutes per present * 20 presents = 100 minutes
Luke:
y = 4 minutes per present * 20 presents = 80 minutes
Answers
1/2 is equivalent to 0.5
1 is equivalent to 1.0
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add t to s
raise the result to the 10th power
then double what you have
Although the gardener applies the same amount of force to the wheelbarrow, he cannot move it with the same rate of acceleration.
What should the gardener do to move the wheelbarrow at the same rate of acceleration for the second trip?
A. reduce the amount of soil by one-half and apply the same amount of force
B. keep the amount of soil the same and apply less force
C. reduce the amount of soil by one-quarter and apply the same amount of force
D. double the amount of soil, and apply less force
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Answer:
Step-by-step explanation:
it seems to me that if he wants the same rate of acceleration as the first trip, then he would need the same amount of soil as the first trip.
Therefore, he should reduce the amount of soil by one half and apply the same force. <====
Because the first time it was half full.....and since the second trip was all the way full, if he reduced it by one half, it would contain the same amount as the first trip....so he can then get the same rate of acceleration.
Answer:
A.
Step-by-step explanation:
According to Newton's second law of motion, an object with a larger mass requires more force to accelerate it at a certain rate than an object with less mass. This means that an object with a larger mass requires more force to accelerate.
To move the wheelbarrow at the same rate of acceleration for the second trip, the amount of soil must be the same as in the first trip. Since the gardener first filled only one-half of the wheelbarrow with soil, the gardener must reduce the amount of soil by one-half and apply the same amount of force.