HELP ! Find the Domain in this question

Answers

Answer 1

Answer: See that denominator cannot be zero, so,

x-3 ≠ 0
x ≠ 3

Domain:

S={x∈R/x≠3}

Answer 2

Answer: $x-3\not=0\n x\not=3\n D:x\in\mathbb{R}\setminus\{3\}$

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In order to gather experts to advise him on federal policy, President George Washington createdCongress.
the Constitution.
a cabinet.
departments.

Answers

Answer:

C.- A cabinet

hope this helped

Step-by-step explanation:

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try to get to 34 thanks and ill answer all your question or go on my page and give me a thanks

Question 2 An exponential model y = a.6 passes through the points (0,9) and (3,243). What are the values of a and b?

Answers

Answer:

a = 9, b = 3

Step-by-step explanation:

The exponential function is

y = a $b^(x)$

Find a and b by using the points it passes through

Using (0, 9 ) then

9 = a $b^(0)$ ( $b^(0)$ = 1 )

a = 9

y = 9 $b^(x)$

Using (3, 243 ) then

243 = 9b³ ( divide both sides by 9 )

27 = b³ ( take the cube root of both sides )

b = $\sqrt[3]{27}$ = 3

y = 9 $(3)^(x)$ ← exponential equation

What is the value of | –29 |?A.
29

B.
–29

think its A=29

Answers

Yep its A) 29

because that symbol is the absolute value symbol meaning its is always turned into a positive.

Yes it is A.29 becouse | | symbol value

Put these numbers in order from least to greatest 11, 7, 8, 3, 6, three, 16, 10, 16

Answers

3, three, 6, 7, 8,10,16,16

3 , 3 , 6 , 7 , 8 , 10 , 11 , 16 , 16

hope this helps you

A single-cell amoeba doubles every 3 days. how long would it take on amoeba to produce a population of about 10,000 amoebae?

Answers

2^n=10,000
2^14=10,000
d=3n
d=3(14)
d=42

d=days
n=number of times of reproduction

Final answer:

It would take approximately 30 days for a single-cell amoeba to produce a population of about 10,000 amoebae.

Explanation:

To find out how long it would take for a single-cell amoeba to produce a population of about 10,000 amoebae, we need to calculate the number of times the amoeba doubles. Since the amoeba doubles every 3 days, we can find out the number of doubling periods it would take to reach 10,000 amoebae by dividing 10,000 by 2. This equals approximately 9.965, which means the amoeba would need to double about 9.965 times. Since we can't have a fraction of a doubling period, we can round it up to 10.

Each doubling period is 3 days, so to find out how long it would take, we can multiply the number of doubling periods (10) by the time interval for each doubling period (3 days). 10 x 3 = 30. Therefore, it would take approximately 30 days for a single-cell amoeba to produce a population of about 10,000 amoebae.