Find the domain of this question
Find the domain of this question - 1

Answers

Answer 1
Answer: -8 - x ≠ 0
-x ≠ 8
x ≠ -8

So, domain:

D={x∈R / x ≠ 8}
Answer 2
Answer: -8-x\not=0\n x\not=-8\n D:x\in\mathbb{R}\setminus\{-8\}

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Solve for n round to the tenths place 14/21.2= n\15

Find the GCF of the following monomials. -50m 4 n 7 and 40m 2 n 10

Answers

Answer:

10m^2n^7

Step-by-step explanation:

-50m^4n^7 \ and \ 40m^2n^(10)

WE need to find GCf for both monomials. GCF is the greatest common factor

-50 ->-1 \cdot 5 \cdot 5 \cdot 2

40 ->2 \cdot 2 \cdot 5 \cdot 2

GCF is 2 times 5 =10

GCF of exponent is the lowest exponent

GCF of m^4  and m^2 is m^2

GCF of n^7 and n^10 is n^7

-50m^4n^7 \ and \ 40m^2n^(10)

GCF is 10m^2n^7

2 ,     1,    , 2  if it helps <3 

How to find hyptenuse of a triangle?

Answers

IF the triangle has a 90-degree angle in it (it's a right triangle), then the length
of the hypotenuse is:

Square root of (square of the shortest side + square of the medium side).

If the triangle is not a right triangle, then it doesn't have a hypotenuse.

What is the definition of complimentary angles?Two angles that add to be 180°
Two angles that have a difference of 90°
Two angles add to be 90°
Two angles that have a difference of 180°

Answers

Simple, the answer to this is...

two angles that add up to be the sum of 90°

Now, a quick tip.

To know the difference between supplementary (180°) and complementary (90°) angles...

the in supplementary can be viewed as an 8, while in complementary the c can be viewed as a 9....

Thus, your answer....C.

Dan left the city traveling at 87mph, while, Sally left the city going the opposite direction at a speed of 41mph. Find the time Dan traveled before the two were 113 miles apart

Answers

Step-by-step explanation:

10858100817910891900

What is the soultion to the system of equation graphed below ?

Answers

Hello,
answer D (-2,3)

Indeed
y=4x+11
y=-2x-1

==>4x+11=-2x-1
==>6x=-12
==>x=-2

And y=4*(-2)+11=3

Solve using logs 5^(3x-6)=125

Answers

5 ^(3x-6) =125 \n \n 5 ^(3x-6) =5^3 \n \n3x-6 =3 \ \ |+6 \n \n3x=3+9 \n \n3x=12 \ \ /:3 \n \nx=(12)/(3) \n \nx= 3