The running time for movie A is 33 mins more than twice the running time for movie B. If the running time for movie A is subtracted from triple the running time for movie B, the result is 57 mins. find the running time for each movie..Movie A-
Movie B-
Answers
Answer 1
Answer:
X is the running time for movie A and y the running time for movie B
X = 2y + 33
3y - × = 57
x- 2y = 33
-× + 3y = 57 => y = 90
=> x 33 + 180 = 213
X = 2y + 33
3y - × = 57
x- 2y = 33
-× + 3y = 57 => y = 90
=> x 33 + 180 = 213
Answer 2
Answer:
use what they tell you to create the equations
a=33+2b & 57=3b-a
for this to work we need to substitute a variable to get rid of it.
look at
57=3b-a (lets switch it around s that the equation reads "a=")
57+a=3b
a=3b-57 (this is our new equations)
so now we know that
a=33+2b & a=3b-57
so we can write 33+2b=3b-57. we have now "gotten rid" of "a"
SOLVE FOR B
33+2b=3b-57 (get variable alone)
33= 3b-2b-57 (subtract and add accordingly)
33= b-57
33+57=b
90=b (this means that movie b is 90 long)
SOLVE FOR A
you can plug "b" into any of the original equations.
a=33+2b
a=33+2(90)
a=33+180
a=213
CHECK
plug "a" into any of the original equations to find "b" if b=90 then you know you've done it right
213=33+2b
213-33=2b
180=2b
180/2=b
90=b
hope this helps :)
a=33+2b & 57=3b-a
for this to work we need to substitute a variable to get rid of it.
look at
57=3b-a (lets switch it around s that the equation reads "a=")
57+a=3b
a=3b-57 (this is our new equations)
so now we know that
a=33+2b & a=3b-57
so we can write 33+2b=3b-57. we have now "gotten rid" of "a"
SOLVE FOR B
33+2b=3b-57 (get variable alone)
33= 3b-2b-57 (subtract and add accordingly)
33= b-57
33+57=b
90=b (this means that movie b is 90 long)
SOLVE FOR A
you can plug "b" into any of the original equations.
a=33+2b
a=33+2(90)
a=33+180
a=213
CHECK
plug "a" into any of the original equations to find "b" if b=90 then you know you've done it right
213=33+2b
213-33=2b
180=2b
180/2=b
90=b
hope this helps :)
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Well to put it in numbers, he has 4 3/4 feet of rope. He wants to cut off 1 1/2.
First we need to get common fractions. The way we do this is: is there anyway to make a 2, a four? Yes! There is! (If there is not, you have to find the Least common multiple)
How do we make this two a four? we times it by 2! But we have to be nice, and multiply the whole fraction, just to be fair.
So, we now have 4 3/4 rope, and James wants to get rid of 1 2/4 rope.
For starters, lets go easy. He has 4 foot, he wants one gone. So he has 3 feet of rope left.
But we still have the fractions! He has 3/4 rope, and we want to get rip of 2/4! so we subtract the numerators, and are left with 1/4 (its important you remember to keep the denominator in this case!)
So if we combine that, James will be left with 3 1/4 feet of rope!
First we need to get common fractions. The way we do this is: is there anyway to make a 2, a four? Yes! There is! (If there is not, you have to find the Least common multiple)
How do we make this two a four? we times it by 2! But we have to be nice, and multiply the whole fraction, just to be fair.
So, we now have 4 3/4 rope, and James wants to get rid of 1 2/4 rope.
For starters, lets go easy. He has 4 foot, he wants one gone. So he has 3 feet of rope left.
But we still have the fractions! He has 3/4 rope, and we want to get rip of 2/4! so we subtract the numerators, and are left with 1/4 (its important you remember to keep the denominator in this case!)
So if we combine that, James will be left with 3 1/4 feet of rope!
Answers
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1/20 converted to a decimal is 1 divided by 20
you divide the numerator by the denominator
technically 1/20 in not a mixed number but if you did have a mixed number first you would convert it into an improper fraction for example 7 1/4 you would change it to 29/4 then you would divide 29 by 4 your answer to that would be 7.25 (also 1/20 as a decimal would be 0.05
a. the tiger
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d. humankind
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Answers
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Answers
-3(2)(-4)+4(2)-3=24+8-3=29
Hi
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32 - 3
= 29
I hope that's help !
-3mn + 4m -3 when m =2 and n=-4
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24 + 8 -3
32 - 3
= 29
I hope that's help !
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