five decimals that have at least 3 digits to the right of the decimal point. write the expanded form of the word form for each number

Answers

Answer 1

Answer: 1. Decimal Form: 1.567
Word Form: One and five hundred sixty seven thousandths
Expanded Form: 1+0.5+0.06+0.007

2. Decimal Form: 2.329
Word Form: Two and three hundred twenty nine thousandths
Expanded Form: 2+0.3+0.02+0.009

3. Decimal Form: 3.486
Word Form: Three and four hundred eighty six thousandths
Expanded Form: 3+0.4+0.08+0.006

4. Decimal Form: 4.351
Word Form: Four and three hundred fifty one thousandths
Expanded Form: 4+0.3+0.05+0.001

5. Decimal Form: 5.768
Word Form: Five and seven hundred sixty eight thousandths
Expanded Form: 5+0.7+0.06+0.008

Hope I helped !!! :-)

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A tablet weighs 1.23 pounds. What is its weight written as a mixed number?

Answers

The weight that should be written as the mixed number should be $1 (23)/(100)$

Given that,

The table weight is 1.23 pounds.

Here we need to find out the weight that should be written as the mixed number.

So first we have to understand what is the mixed number i.e. described below.

A mixed number should be the mix of the whole number & the fraction.

So, the weight written as the mixed number should be $1 (23)/(100)$

Learn more about the number here: brainly.com/question/17429689

If a tablet weighs 1.23 pounds, the weight written as a mixed number would be, 1 as the whole number and 23 is in the hundreds place, so you would write, 1 and 23/100.

In APQR, ZQ = ZP, RP = 13 and PQ = 19. Find the length of QR.

Answers

Answer:

Step-by-step explanation:

∠Q ≅ ∠ P ⇒ RP = RQ = 13

At a carnival, food tickets cost $2 each and ride tickets cost $3 each. A total of $1,240 was collected at the carnival. The number of food tickets sold was 10 less than twice the number of ride tickets sold.The system of equations represents x, the number of food tickets sold, and y, the number of ride tickets sold.

2x + 3y = 1240

x = 2y – 10

How many of each type of ticket were sold?

Answers

Answer:

Here, x represents the umber of food tickets sold and y represents the number of ride tickets sold.

Given the system of equations:

$2x+3y = 1240$ ....[1]

$x = 2y-10$ ....[2]

Substitute the equation [2] into [1] we have;

$2(2y-10)+3y = 1240$

Using distributive property,

$a \cdot(b+c) = a\cdot b+ a\cdot c$

$4y-20+3y = 1240$

Combine like terms;

$7y-20 = 1240$

Add 20 to both sides we have;

$7y= 1260$

Divide both sides by 7 we have;

y = 180

Substitute this in [2] we have;

$x = 2(180)-10 = 360-10 = 350$

therefore, each type of ticket were sold are:

the number of food tickets sold is, 350 and the number of ride tickets sold is, 180

2(2y-10)+3y=1240
7y-20=1240
7y=1260
y=180
2x+3(180)=1240
2x+540=1240
2x=700
x=350
So they sold 350 food tickets and 180 ride tickets in total.
#TeamAlvaxic

Can someone may help me with solving system of solving equations plzA small soda costs $0.45 and a large soda costs $0.65. 35 sodas were sold for a total of $18.55. How many of each size soda were sold?

Answers

let number of small sodas sold be x
# of large sodas sold be y
so
x + y =35
x=35 - y {equation1}
now next equation
0.65x + 0.45y = 18.55 { divide all by 0.50}
1.3x + 0.9y = 37.1 { put x = 35 - y (from eq 1)}
1.3 (35 - y) +0.9y = 37.1
45.5 - 1.3y + 0.9y = 37.1 {subtract 45.5 from both sides}
-0.4y = -8.4 { divide both by -0.4}
y = 21
so #of large sodas sold is 21
# of small sodas sold is 35 -21 = 14

Solve for x in simplest form. 4=1/3(7x-3)

Answers

Answer:

x=15 over 7

Hope this helps

Step-by-step explanation:

Write an equation of a line in slope-intercept form if the slope is ½ and the y-intercept is -2.(A) y = (½)x + 2
(B) x - 2y = -4
(C) y = (½)x - 2
(D) 2y = x + 4

Answers

I was just learning about this. Okay,
First we need to plug in the values of the slope intercept form y = mx + b. b is the y-intercept so it is -2.

y = mx + -2.

Now lets find the rate of change or mx. the slope is 1/2 so the rate of change is 1/2. Lets plug in the value.

y = 1/2x + -2

The answer is A. Hope this helped!!

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