Thirty pounds of a salt-water solution contains fifteen percent salt. How much water must be added to weaken the solution to ten percent salt?

Answers

Answer 1

Answer: $Formula\ for\ percen\ concentration:\n Cp=(ms)/(mr)*100\%\n\n ms-mass \ of\ substance\n mr- mass\ of \ solution\n\n mr=30 pound\n ms=x\n 30 \ pounds\ of \ salt-water\ solution-----cp=15\%\n 30 \ pounds\ of \ salt-water\ solution + x\ water --cp=10\%\n 15\%=(ms)/(30)*100\% \n (15)/(100)=(ms)/(30)\n 100ms=15*30\ |:100\n ms=4,5\ pound\n 10\%=(ms)/(30+x)*100\%\n (10)/(100)=(4,5)/(30+x)\n 10(30+x)4,5*100\n 300+10x=450\n 10x=150\ |:10\n x=15 pound\n$ $15\ pounds\ of\ water\ must\ be\ added.$

Answer 2

Answer:

15 lb to i belive it to i fyou use the furmoata

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Jim goes canoeing on a local stream that has been measured to flow at 2 mph. If he can go 9 miles upstream in the same time it takes him to go 15 miles downstream, find how fast he can go in still waters.

Answers

Answer: This is a problem of solving a system of linear equations. Let x be the speed of Jim in still waters, and y be the speed of the stream. Then we have:

{x+y=15/tx−y=9/t

where t is the time it takes Jim to go upstream or downstream. We can solve this system by adding the two equations and eliminating y:

2x=24/tx=12/t

Then we can substitute x into one of the equations and solve for y:

y=15/t−12/ty=3/t

Since we know that the speed of the stream is 2 mph, we can equate y to 2 and solve for t:

3/t=2t=3/2

Finally, we can plug in t into the expression for x and find the speed of Jim in still waters:

x=12/tx=12/(3/2)x=8

Therefore, Jim can go 8 mph in still waters.

Answer:

Time taken to go downstream = 4 / ( 2 + S) where S is the speed of the river

TIme taken to go upstream = 1 / ( 2 - S )

Since the time taken is the same in each case we can equate both of them

1 / ( 2 - S) = 4 / ( 2 + S )

2 + S = 8 - 4S

5 S = 6

S = 6 / 5

= 1.2 mph

How many combinations of 3 rocks can you choose from 8 rocks

Answers

2 because 3 times 2 is 6, so if u did 3 times 3 it would be too high to instead it would be 2

A fruit company delivers its fruit in two types of boxes : large and small. A delivery of 6 large boxes and 5 small boxes has a total weight of 190 kilograms. A delivery of 2 large boxes and 3 small boxes has a total of 84 kilograms. How much does each type of boxes weigh ?

Answers

4 large and 8 small weigh 113kg
so
2 large and 4 small weigh 56.5 kg
but
2 large and 3 small weigh 50 kg
so taking the difference
1 small weighs 56.5 - 50 = 6.5 kg.

Substitute :
2 large and 3 small weight 50 kg
2 large weigh 50 - 3*6.5 = 50 - 19.5 = 30.5 kg
1 large weighs 15.25 kg

We have this system

6L + 5S = 190 (1)

2L + 3S = 84 multiply through by -3 ⇒ -6L - 9S = -252 (2)

Add (1) and (2) and we get that

-4S = -62

S = -62 / -4 = 15.5 kilos for a small box

And

2L + 3S = 84

2L + 3 (15.5) = 84

2L = 46.5 = 84

2L = 84 - 46.5

2L = 37.5

L = 37.5 /2 = 18.75 kilos for a large box

How much does 3000 kg = to get tons

Answers

1 ton= 1000 kg
3000 kg= 3 ton

again
1000kg = 1ton
3000kg = 3 tons

A box plot was made to represent the number of matches won by 14 participants in a tennis tournament. The box plot was symmetric. Based on the box plot, which conclusion is most likely correct?A) There are no participants who won an exceptionally large or small number of matches compared to other participants.
B) The mean of matches won by participants is more than the median of matches won by participants.
C) Most of the participants won many matches, but some participants won very few matches compared to the others.
D) Most of the participants won very few matches, but some participants won many matches compared to the others.

Answers

If we have drawn a box plot to represent number of matches won by 14 participants in a tennis tournament, and got that the box plot was symmetric . It means

1 . There are equal number of values that is points obtained by 14 participants , on both side of a line drawn from the middle of the curve , there are equal number of points.

Symmetric means, → Median = Mean

→The point graph representing number of points obtained by 14 players is divided into two congruent parts or curves have equal areas.

So, we can conclude that

Option (A):There are no participants who won an exceptionally large or small number of matches compared to other participants.

Answer: The correct answer is option A.

Manuel has $600 in a savings account at the beginning of the summer. He wants to have at least $300 in the account at the end of the summer. He withdraws $28 each week for food. Which inequality represents w, the number of weeks Manuel can withdraw money while not dropping below a $300 balance?28-600w < 300

28-600w > 300

600-28w < 300

600-28w > 300

Answers

The answer to this question is 600-28w > 300. This inequality can be described as $600 (money in the savings account) subtracted by $28w (withdrawal of $28 a week for food) should be greater than $300. It proves that the money will not drop below $300.

it would be the 3rd one i just took the test

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